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Question Number 116079 Answers: 1 Comments: 0

prove that Re=((ρ∙v∙d)/μ) renulds number

$p r o v e t h a t R e = \frac{ρ \cdot v \cdot d}{μ} r e n u l d s n u m b e r$

Question Number 116078 Answers: 1 Comments: 0

prove that Fr=(v^2 /(gh)) froude numer

$p r o v e t h a t F r = \frac{v^{2}}{g h} f r o u d e n u m e r$

Question Number 113829 Answers: 0 Comments: 0

what is the darcy formula for laminar flow?

$w h a t i s t h e d a r c y f o r m u l a f o r$ $l a m i n a r f l o w ?$

Question Number 80798 Answers: 0 Comments: 1

Question Number 66106 Answers: 1 Comments: 0

In an electrolysis experiment, the ammeter records a steady current of 1A. The mass of copper deposited in 30minutes is 0.66g. Calculate the error in the ammeter reading. the electrical equivalent of cu is 3.3×10^(−4) g/C.

$In an electrolysis experiment, the ammeter$ $records a steady current of 1 A . The mass$ $of copper deposited in 30 minutes is 0 . 66 g .$ $Calculate the error in the ammeter reading .$ $the electrical equivalent of cu is 3.3 \times 10^{- 4} g / C .$

Question Number 63137 Answers: 1 Comments: 0

please who can prove the half−life in radioactivity formula of t_(1/2) = ((ln2)/λ) where λ is distergration rate. Involving ln(N_0 /N_t )= λt

$p l e a s e w h o c a n p r o v e t h e h a l f - l i f e i n r a d i o a c t i v i t y f o r m u l a$ $o f t_{\frac{1}{2}} = \frac{l n 2}{λ} w h e r e λ i s d i s t e r g r a t i o n r a t e . I n v o l v i n g$ $l n \frac{N_{0}}{N_{t}} = λ t$

Question Number 61993 Answers: 1 Comments: 0

ultraviolet light of wavelength 300×10^(−9) m causes photon emissions from a surface The stopping potential is 6V.Find the work-function in electron-Volts

$u l t r a v i o l e t l i g h t o f w a v e l e n g t h 300 \times 10^{- 9} m$ $c a u s e s p h o t o n e m i s s i o n s f r o m a s u r f a c e$ $T h e s t o p p i n g p o t e n t i a l i s 6 V . F i n d t h e$ $w o r k - f u n c t i o n i n e l e c t r o n - V o l t s$

Question Number 61297 Answers: 0 Comments: 0

A container is 50% full of water at triple point phase . It′s Isolated and subjected to space system defining no gravity acting on the particles , Which state of matter is now more dominant , solid , liquid , or gas ? Calculate the intermolecular distances between simultaneous two distinct states of water.

$A container is 50 % full of water at triple point$ $phase . {It}^{'} s Isolated and subjected to space$ $system defining no gravity acting on the$ $particles, Which state of matter is now$ $more dominant, solid, liquid, or gas ?$ $Calculate the intermolecular distances$ $between simultaneous two distinct states$ $of water .$

Question Number 53998 Answers: 0 Comments: 1

In the next link, Barry Barrish, who won the physic nobel prize in 2017; gave an exclusive interview to IFT-Instituto de Fisica Teo^ rica-(part 1):

$In the next link, Barry Barrish, who won the physic nobel prize in 2017;$ $gave an exclusive interview to IFT - I n s t i t u t o d e F i s i c a T e \overset{´}{o r i c a} - (part 1) :$

Question Number 53852 Answers: 0 Comments: 0

G_(μν) = R_(μν) − (1/2) Rg_(μν) + 𝚲g_(μν) Wich theory of modern physic belongs this equation? and what does it mean?

$G_{μ ν} = R_{μ ν} - \frac{1}{2} {R g}_{μ ν} + Λ g_{μ ν}$ $Wich theory of modern physic belongs this equation ?$ $and what does it mean ?$

Question Number 53165 Answers: 2 Comments: 0

Question Number 52846 Answers: 1 Comments: 0

Question Number 52845 Answers: 1 Comments: 0

Question Number 52457 Answers: 1 Comments: 0

Two radioactive elements A and B has half lives of 100 and 50years. Samples of A and B initial contains equal numbers of atoms.What is the ratio of the remaining atoms of A to that of B after 200years?

$T w o r a d i o a c t i v e e l e m e n t s A a n d B$ $h a s h a l f l i v e s o f 100 a n d 50 y e a r s .$ $S a m p l e s o f A a n d B i n i t i a l c o n t a i n s$ $e q u a l n u m b e r s o f a t o m s . W h a t i s$ $t h e r a t i o o f t h e r e m a i n i n g a t o m s$ $o f A t o t h a t o f B a f t e r 200 y e a r s ?$

Question Number 45748 Answers: 0 Comments: 1

Question Number 45747 Answers: 1 Comments: 0

Question Number 45746 Answers: 0 Comments: 1

Question Number 45646 Answers: 0 Comments: 2

According to relativistic theory, E^2 = p^2 c^2 +m_0 ^2 c^4 where m_0 is rest mass. For photon E= pc... (m_0 =0 for photon) For electron E=mc^2 ... Unlike photon ,Why p^2 c^2 is neglected in case of electron ?

$A c c o r d i n g t o r e l a t i v i s t i c t h e o r y,$ $E^{2} = p^{2} c^{2} + m_{0}^{2} c^{4} w h e r e m_{0} i s r e s t m a s s .$ $F o r p h o t o n E = p c . . .$ $(m_{0} = 0 f o r p h o t o n)$ $F o r e l e c t r o n E = {m c}^{2} . . .$ $U n l i k e p h o t o n, W h y p^{2} c^{2} i s n e g l e c t e d$ $i n c a s e o f e l e c t r o n ?$

Question Number 45539 Answers: 1 Comments: 2

Question Number 44005 Answers: 0 Comments: 0

Question Number 41371 Answers: 1 Comments: 1

Calculate the amount of energy⊛ released when carbon-12 nucleus is formed by bringing 6 neutrons and 6 protons together.

$C a l c u l a t e t h e a m o u n t o f e n e r g y ⊛$ $r e l e a s e d w h e n c a r b o n - 12 n u c l e u s$ $i s f o r m e d b y b r i n g i n g 6 n e u t r o n s$ $a n d 6 p r o t o n s t o g e t h e r .$

Question Number 41373 Answers: 0 Comments: 1

when uranium-235 undergoes nuclear fission,0.01% of its mass is converted to energy.(a)Calculate the energy released when 1gm of Uranium-235 undergoes nuclear fission.(b)What is the amount of uranium-235 that will undergo nuclear fission reaction every hour in a nuclear reactor that provides 100 megawatts of electric power?

$w h e n u r a n i u m - 235 u n d e r g o e s$ $n u c l e a r f i s s i o n, 0 . 01 % o f i t s m a s s$ $i s c o n v e r t e d t o e n e r g y . (a) C a l c u l a t e$ $t h e e n e r g y r e l e a s e d w h e n 1 g m o f$ $U r a n i u m - 235 u n d e r g o e s n u c l e a r$ $f i s s i o n . (b) W h a t i s t h e a m o u n t o f$ $u r a n i u m - 235 t h a t w i l l u n d e r g o$ $n u c l e a r f i s s i o n r e a c t i o n e v e r y h o u r$ $i n a n u c l e a r r e a c t o r t h a t p r o v i d e s$ $100 m e g a w a t t s o f e l e c t r i c p o w e r ?$

Question Number 41361 Answers: 1 Comments: 0

The half life of radium-226 is 1620 years.Calculate (a)the decay constant (b)the time it takes 60% of a given sample to decay, and (c)the initial activity of 1gm of pure radium-226

$T h e h a l f l i f e o f r a d i u m - 226 i s 1620$ $y e a r s . C a l c u l a t e (a) t h e d e c a y c o n s t a n t$ $(b) t h e t i m e i t t a k e s 60 % o f a g i v e n$ $s a m p l e t o d e c a y, a n d (c) t h e i n i t i a l$ $a c t i v i t y o f 1 g m o f p u r e r a d i u m - 226$

Question Number 41148 Answers: 1 Comments: 0

Calculate the speed of an electron whose kinetic energy is equal to 2% of its rest mass.

$C a l c u l a t e t h e s p e e d o f a n e l e c t r o n$ $w h o s e k i n e t i c e n e r g y i s e q u a l t o$ $2 % o f i t s r e s t m a s s .$

Question Number 34170 Answers: 1 Comments: 0

the distance from A to B is 44km the speed of a car is 2kms^(−1) find the term hence the amount of money needed to buy fuel if for every 6km 10 l of fuel is used which causes 600 box.

$t h e d i s t a n c e f r o m A t o B i s 44 k m$ $t h e s p e e d o f a c a r i s 2 {k m s}^{- 1} f i n d$ $t h e t e r m h e n c e t h e a m o u n t o f$ $m o n e y n e e d e d t o b u y f u e l i f f o r$ $e v e r y 6 k m 10 l o f f u e l i s u s e d w h i c h$ $c a u s e s 600 b o x .$

Pg 1 Pg 2 Pg 3

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