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Question Number 103969 Answers: 1 Comments: 0

how do you solve (D^3 +12D^2 +36D)y=0 by constant coefficients

$h o w d o y o u s o l v e (D^{3} + 12 D^{2} + 36 D) y = 0$ $b y c o n s t a n t c o e f f i c i e n t s$

Question Number 103008 Answers: 2 Comments: 0

(dy/dx) − y.tan x = e^x .sec x

$\frac{d y}{d x} - y . \tan x = e^{x} . \sec x$

Question Number 101303 Answers: 1 Comments: 1

i^i^(i.∞) =?

$i^{i^{i . \infty}} = ?$

Question Number 100327 Answers: 1 Comments: 1

Solve x^2 y′′−3xy′−5y=0

$S olve x^{2} y^{″} - {3 xy}^{'} - 5 y = 0$

Question Number 96138 Answers: 0 Comments: 1

xy′ + y^2 = x^2 e^x

${x y}^{'} + y^{2} = x^{2} e^{x}$

Question Number 78333 Answers: 1 Comments: 0

prove by contradiction that (√(2 )) is irrational.

$prove by contradiction that \sqrt{2} is irrational .$

Question Number 77330 Answers: 0 Comments: 3

Question Number 75821 Answers: 0 Comments: 1

Question Number 73247 Answers: 1 Comments: 0

Question Number 66875 Answers: 0 Comments: 4

Question Number 66418 Answers: 0 Comments: 0

what operation on interger used in 9(7.8)=(9.7).8??

$w h a t o p e r a t i o n o n i n t e r g e r u s e d i n 9 (7.8) = (9.7) . 8 ? ?$

Question Number 63298 Answers: 0 Comments: 2

A particle P, moves on the curve with polar equation r = e^(kθ) , where (r,θ) are polar coordinates referred to a fixed pole and k is a positive constant. Given that the radial velocity of P is (k/r) show that the transverse acceleration of th particle is zero.

$A p a r t i c l e P, m o v e s o n t h e c u r v e w i t h p o l a r e q u a t i o n$ $r = e^{k θ}, w h e r e (r, θ) a r e p o l a r c o o r d i n a t e s r e f e r r e d t o a f i x e d$ $p o l e a n d k i s a p o s i t i v e c o n s t a n t . G i v e n t h a t t h e r a d i a l v e l o c i t y$ $o f P i s \frac{k}{r} s h o w t h a t t h e t r a n s v e r s e a c c e l e r a t i o n o f t h p a r t i c l e$ $i s z e r o .$

Question Number 47235 Answers: 0 Comments: 0

the force acting on a particle P of mass 2kg is (2ti +4j)N. P is initially at rest at point with position vector (i+2j). Find the velocity of P when t=2 and the position vector when t=2.

$t h e f o r c e a c t i n g o n a p a r t i c l e P o f m a s s 2 k g i s (2 t i + 4 j) N .$ $P i s i n i t i a l l y a t r e s t a t p o i n t w i t h p o s i t i o n v e c t o r (i + 2 j) .$ $F i n d t h e v e l o c i t y o f P w h e n t = 2 a n d t h e p o s i t i o n v e c t o r$ $w h e n t = 2 .$

Question Number 47234 Answers: 0 Comments: 0

the force acting on a particle P of mass 2kg is (2ti +4j)N. P is initially at rest at point with position vector (i+2j). Find the velocity of P when t=2 and the position vector when t=2.

Question Number 47233 Answers: 0 Comments: 0

the force acting on a particle P of mass 2kg is (2ti +4j)N. P is initially at rest at point with position vector (i+2j). Find the velocity of P when t=2 and the position vector when t=2.

Question Number 47138 Answers: 0 Comments: 0

Question Number 42316 Answers: 1 Comments: 2

Question Number 41388 Answers: 0 Comments: 1

Question Number 26557 Answers: 0 Comments: 0

Question Number 25310 Answers: 0 Comments: 0

Question Number 11261 Answers: 0 Comments: 0

The n^(th) term of a progression is np+q and the sum of n terms is denoted by S_n . Given that the 6^(th) term is 4 times 2^(nd) term and that S_3 =12, find the value of p and q. Express S_n in terms of n.

$The n^{th} term of a progression is np + q and the sum of n terms is denoted by S_{n} .$ $Given that the 6^{th} term is 4 times 2^{nd} term and that S_{3} = 12, find the value of p and q .$ $Express S_{n} in terms of n .$

Question Number 9420 Answers: 0 Comments: 0

x and y are two binary numbers which are in 4 − bit 2′s complement formate, where x = 00102 and y = 11012 : clearly, y is a negative number. what is the result of x + y in decimal formate.

$x and y are two binary numbers which are$ $in 4 - bit 2^{'} s complement formate,$ $where x = 00102 and y = 11012 : clearly,$ $y is a negative number . what is the result$ $of x + y in decimal formate .$

Question Number 9419 Answers: 0 Comments: 0

Develop an algorithm and draw a flowchat to find the sum of numbers from 1 − 100

$Develop an algorithm and draw a flowchat$ $to find the sum of numbers from 1 - 100$

Question Number 5453 Answers: 0 Comments: 0

$g n$

Question Number 5458 Answers: 0 Comments: 0

=7↽

$= 7 ↽$

Question Number 2032 Answers: 0 Comments: 1

f:[0,+1]→R η(f):=∫_0 ^1 f^2 dx and if ∀x∈[0,1],f∈[m,M] for some (m,M)∈R^2 f↑:=max(f)−f f↓:=f−min(f) μ(f):=∫_0 ^1 f↓f↑dx then f=e^x , η(f)=^? μ(f) f=x,η(f)=^? μ(f) ∃f,η(f)=0??? ∃f,μ(f)=0??? μ(f)=0, does η(f)=0??? η(f)=0, does μ(f)=0???

$f : [0, + 1] \to R$ $η (f) := \underset{0}{\int^{1}} f^{2} d x$ $and if \forall x \in [0, 1], f \in [m, M] for some (m, M) \in R^{2}$ $f ↑:= \max (f) - f$ $f ↓:= f - \min (f)$ $μ (f) := \underset{0}{\int^{1}} f ↓ f ↑ d x$ $then$ $f = e^{x}, η (f) \overset{?}{=} μ (f)$ $f = x, η (f) \overset{?}{=} μ (f)$ $\exists f, η (f) = 0 ? ? ?$ $\exists f, μ (f) = 0 ? ? ?$ $μ (f) = 0, does η (f) = 0 ? ? ?$ $η (f) = 0, does μ (f) = 0 ? ? ?$

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