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Question Number 22879    Answers: 1   Comments: 0

The Enthalpy of neutralization of acetic acid and sodium hydroxide is −55.4 kJ. What is the enthalpy of ionisation of acetic acid?

TheEnthalpyofneutralizationofaceticacidandsodiumhydroxideis55.4kJ.Whatistheenthalpyofionisationofaceticacid?

Question Number 22884    Answers: 1   Comments: 0

A body of mass 0.3 kg is taken up an inclined plane of length 10 m and height 5 m, and then allowed to slide down to the bottom again. The coefficient of friction between the body and the plane is 0.15. What is the kinetic energy of the body at the end of the trip?

Abodyofmass0.3kgistakenupaninclinedplaneoflength10mandheight5m,andthenallowedtoslidedowntothebottomagain.Thecoefficientoffrictionbetweenthebodyandtheplaneis0.15.Whatisthekineticenergyofthebodyattheendofthetrip?

Question Number 22837    Answers: 0   Comments: 0

The effective nuclear charge of N on its last electron is:−

TheeffectivenuclearchargeofNonitslastelectronis:

Question Number 22813    Answers: 1   Comments: 0

The nucleus Fe^(57) emits a γ-ray of energy 14.4 keV. If the mass of the nucleus is 56.935 u, calculate the recoil energy of nucleus.

ThenucleusFe57emitsaγrayofenergy14.4keV.Ifthemassofthenucleusis56.935u,calculatetherecoilenergyofnucleus.

Question Number 22797    Answers: 1   Comments: 0

He^+ in ground state is hit by photon thus exciting electron to second excited state. The energy absorbed in this process is (approx) (1) 2.18 × 10^(−14) J (2) 7.75 × 10^(−18) J (3) 4.5 × 10^(−18) J (4) 5 × 10^(−18) J

He+ingroundstateishitbyphotonthusexcitingelectrontosecondexcitedstate.Theenergyabsorbedinthisprocessis(approx)(1)2.18×1014J(2)7.75×1018J(3)4.5×1018J(4)5×1018J

Question Number 22782    Answers: 0   Comments: 6

Successive ionisation energies of element is 738, 1450, 10540, 13630 kJ/mole respectively. The element is (1) Na (2) Mg (3) Al (4) K

Successiveionisationenergiesofelementis738,1450,10540,13630kJ/molerespectively.Theelementis(1)Na(2)Mg(3)Al(4)K

Question Number 22744    Answers: 0   Comments: 1

How can i copy and paste from this keyboard to other apps in my mobile? i can copy but can not getting paste in other apps. what to do?

Howcanicopyandpastefromthiskeyboardtootherappsinmymobile?icancopybutcannotgettingpasteinotherapps.whattodo?

Question Number 22743    Answers: 1   Comments: 0

The Enthalpy of neutralization of acetic acid and sodium hydroxide is −55.4 kJ. What is the enthalpy of ionisation of acetic acid?

TheEnthalpyofneutralizationofaceticacidandsodiumhydroxideis55.4kJ.Whatistheenthalpyofionisationofaceticacid?

Question Number 22703    Answers: 1   Comments: 1

Question Number 22692    Answers: 1   Comments: 1

Question Number 22679    Answers: 0   Comments: 3

Maximum covalency of nitrogen is equal to

Maximumcovalencyofnitrogenisequalto

Question Number 22657    Answers: 0   Comments: 0

A real image 3 times the size of the object formed by a concave mirror on a screen. later both the object & the screen are shifted untill the image formed is 6 times the size of the object. if the distnce moved is 15cm. calculate the focal length of the mirror.

Arealimage3timesthesizeoftheobjectformedbyaconcavemirroronascreen.laterboththeobject&thescreenareshifteduntilltheimageformedis6timesthesizeoftheobject.ifthedistncemovedis15cm.calculatethefocallengthofthemirror.

Question Number 22652    Answers: 0   Comments: 0

Find the number of unordered pairs {A, B} (i.e., the pairs {A, B} and {B, A} are considered to be the same) of subsets of an n-element set X which satisfy the conditions: (a) A ≠ B; (b) A ∪ B = X [e.g., if X = {a, b, c, d}, then {{a, b}, {b, c, d}}, {{a}, {b, c, d}}, {φ, {a, b, c, d}} are some of the admissible pairs.]

Findthenumberofunorderedpairs{A,B}(i.e.,thepairs{A,B}and{B,A}areconsideredtobethesame)ofsubsetsofannelementsetXwhichsatisfytheconditions:(a)AB;(b)AB=X[e.g.,ifX={a,b,c,d},then{{a,b},{b,c,d}},{{a},{b,c,d}},{ϕ,{a,b,c,d}}aresomeoftheadmissiblepairs.]

Question Number 22624    Answers: 1   Comments: 0

A uniform chain of length L and mass M is lying on a smooth table and one third of its length is hanging vertically down over the edge of the table. If g is acceleration due to gravity, calculate work required to pull the hanging part on the table.

AuniformchainoflengthLandmassMislyingonasmoothtableandonethirdofitslengthishangingverticallydownovertheedgeofthetable.Ifgisaccelerationduetogravity,calculateworkrequiredtopullthehangingpartonthetable.

Question Number 23793    Answers: 1   Comments: 1

Question Number 22594    Answers: 1   Comments: 0

ΔH_f ^o of water is −285.8 kJ mol^(−1) . If enthalpy of neutralization of monoacid strong base is −57.3 kJ mol^(−1) , ΔH_f ^o of OH^− ion will be

ΔHfoofwateris285.8kJmol1.Ifenthalpyofneutralizationofmonoacidstrongbaseis57.3kJmol1,ΔHfoofOHionwillbe

Question Number 22582    Answers: 1   Comments: 2

A chain consisting of 5 links each of mass 0.1 kg is lifted vertically with a constant acceleration of 2 m/s^2 . The force of interaction (in newton) between the top link and the link immediately below it will be : Take g = 10 m/s^2 .

Achainconsistingof5linkseachofmass0.1kgisliftedverticallywithaconstantaccelerationof2m/s2.Theforceofinteraction(innewton)betweenthetoplinkandthelinkimmediatelybelowitwillbe:Takeg=10m/s2.

Question Number 22574    Answers: 1   Comments: 1

The system is initially at origin and is moving with a velocity (3 m/s) k^∧ . A force (120t newton) i^∧ acts on mass m_2 , where t is time in seconds. The man throws a light ball, at the instant when m_1 starts slipping on m_2 , with a velocity 5 m/s vertically up w.r.t himself. Taking the masses of blocks and man as 60 kg each and assuming that the man never slips on m_2 , find (a) The time at which man throws the ball and (b) The coordinates of the point where ball lands. Neglect the dimensions of the system. (g = 10 m/s^2 )

Thesystemisinitiallyatoriginandismovingwithavelocity(3m/s)k.Aforce(120tnewton)iactsonmassm2,wheretistimeinseconds.Themanthrowsalightball,attheinstantwhenm1startsslippingonm2,withavelocity5m/sverticallyupw.r.thimself.Takingthemassesofblocksandmanas60kgeachandassumingthatthemanneverslipsonm2,find(a)Thetimeatwhichmanthrowstheballand(b)Thecoordinatesofthepointwhereballlands.Neglectthedimensionsofthesystem.(g=10m/s2)

Question Number 22518    Answers: 2   Comments: 1

Question Number 22499    Answers: 1   Comments: 1

A cylinder of weight 200 N is supported on a smooth horizontal plane by a light cord AC and pulled with force of 400 N. The normal reaction at B is equal to

Acylinderofweight200NissupportedonasmoothhorizontalplanebyalightcordACandpulledwithforceof400N.ThenormalreactionatBisequalto

Question Number 22492    Answers: 1   Comments: 1

A ball of mass 400 g travels horizontally along the ground and collides with a wall. The velocity-time graph below represents the motion of the ball for the first 1.2 seconds. The magnitude of average force between the ball and the wall is

Aballofmass400gtravelshorizontallyalongthegroundandcollideswithawall.Thevelocitytimegraphbelowrepresentsthemotionoftheballforthefirst1.2seconds.Themagnitudeofaverageforcebetweentheballandthewallis

Question Number 22487    Answers: 1   Comments: 1

Question Number 22481    Answers: 1   Comments: 1

Question Number 22479    Answers: 0   Comments: 2

A ladder of mass m is leaning against a wall. It is in static equilibrium making an angle θ with the horizontal floor. The coefficient of friction between the wall and the ladder is μ_1 and that between the floor and the ladder is μ_2 . The normal reaction of the wall on the ladder is N_1 and that of the floor is N_2 . If the ladder is about to slip, then (1) μ_1 = 0, μ_2 ≠ 0 and N_2 tan θ = mg/2 (2) μ_1 ≠ 0, μ_2 = 0 and N_1 tan θ = mg/2 (3) μ_1 ≠ 0, μ_2 ≠ 0 and N_2 = ((mg)/(1 + μ_1 μ_2 )) (4) μ_1 = 0, μ_2 ≠ 0 and N_1 tan θ = ((mg)/2)

Aladderofmassmisleaningagainstawall.Itisinstaticequilibriummakinganangleθwiththehorizontalfloor.Thecoefficientoffrictionbetweenthewallandtheladderisμ1andthatbetweenthefloorandtheladderisμ2.ThenormalreactionofthewallontheladderisN1andthatofthefloorisN2.Iftheladderisabouttoslip,then(1)μ1=0,μ20andN2tanθ=mg/2(2)μ10,μ2=0andN1tanθ=mg/2(3)μ10,μ20andN2=mg1+μ1μ2(4)μ1=0,μ20andN1tanθ=mg2

Question Number 22696    Answers: 1   Comments: 5

A force F^→ = 2xj^∧ newton acts in a region where a particle moves anticlockwise in a square loop of 2 m in x-y plane. Calculate the total amount of work done. Is this force a conservative force or a non-conservative force?

AforceF=2xjnewtonactsinaregionwhereaparticlemovesanticlockwiseinasquareloopof2minxyplane.Calculatethetotalamountofworkdone.Isthisforceaconservativeforceoranonconservativeforce?

Question Number 22473    Answers: 0   Comments: 1

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