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Question Number 21713    Answers: 0   Comments: 7

A constant force F = 20 N acts on a block of mass 2 kg which is connected to two blocks of masses m_1 = 1 kg and m_2 = 2 kg. Calculate the accelerations produced in all the three blocks. Assume pulleys are frictionless and weightless.

AconstantforceF=20Nactsonablockofmass2kgwhichisconnectedtotwoblocksofmassesm1=1kgandm2=2kg.Calculatetheaccelerationsproducedinallthethreeblocks.Assumepulleysarefrictionlessandweightless.

Question Number 21670    Answers: 1   Comments: 1

The block of mass 2 kg and 3 kg are placed one over the other. The contact surfaces are rough with coefficient of friction μ_1 = 0.2, μ_2 = 0.06. A force F = (1/2)t N (where t is in second) is applied on upper block in the direction. (Given that g = 10 m/s^2 ) 1. The relative slipping between the blocks occurs at t = 2. Friction force acting between the two blocks at t = 8 s 3. The acceleration time graph for 3 kg block is

Theblockofmass2kgand3kgareplacedoneovertheother.Thecontactsurfacesareroughwithcoefficientoffrictionμ1=0.2,μ2=0.06.AforceF=12tN(wheretisinsecond)isappliedonupperblockinthedirection.(Giventhatg=10m/s2)1.Therelativeslippingbetweentheblocksoccursatt=2.Frictionforceactingbetweenthetwoblocksatt=8s3.Theaccelerationtimegraphfor3kgblockis

Question Number 21661    Answers: 0   Comments: 2

Question Number 21628    Answers: 1   Comments: 0

One end of a massless spring of constant 100 N/m and natural length 0.5 m is fixed and the other end is connected to a particle of mass 0.5 kg lying on a frictionless horizontal table. The spring remains horizontal. If the mass is made to rotate at an angular velocity of 2 rad/s, find the elongation of the spring.

Oneendofamasslessspringofconstant100N/mandnaturallength0.5misfixedandtheotherendisconnectedtoaparticleofmass0.5kglyingonafrictionlesshorizontaltable.Thespringremainshorizontal.Ifthemassismadetorotateatanangularvelocityof2rad/s,findtheelongationofthespring.

Question Number 21626    Answers: 0   Comments: 1

Is it also possible to import text or fomulars from other apps using the android−clipboard?

Isitalsopossibletoimporttextorfomularsfromotherappsusingtheandroidclipboard?

Question Number 21604    Answers: 1   Comments: 0

A particle will leave a vertical circle of radius r, when its velocity at the lowest point of the circle (v_L ) is (a) (√(2gr)) (b) (√(5gr)) (c) (√(3gr)) (d) (√(6gr))

Aparticlewillleaveaverticalcircleofradiusr,whenitsvelocityatthelowestpointofthecircle(vL)is(a)2gr(b)5gr(c)3gr(d)6gr

Question Number 21580    Answers: 1   Comments: 0

Question Number 21564    Answers: 0   Comments: 1

A block of mass M is placed on smooth ground. Its upper surface is smooth and vertical surface is rough with coefficient of friction μ. A block of mass m_1 is placed on its horizontal surface and tied with a massless inextensible string passing over smooth pulley. Its other end is connected to another block of mass m_2 , which touches the vertical surface of block M. Now a horizontal force F starts acting on it. Q1. Which of the following is incorrect about above system? (1) There exists a value of F at which friction force is equal to zero (2) When F = 0, the blocks cannot remain stationary (3) There exists two limiting values of F at which the blocks m_1 and m_2 will remain stationary w.r.t. block of mass M (4) The limiting friction between m_2 and M is independent of F Q2. In the above case, let m_1 − μm_2 be greater than 1. Choose the incorrect value of F for which the blocks m_1 and m_2 remain stationary with respect to M (1) (M + m_1 + m_2 )((m_2 g)/m_1 ) (2) ((m_2 (M + m_1 + m_2 ))/((m_1 − μm_2 )))g (3) (((M + m_1 + m_2 )m_2 g)/((m_1 + μm_2 ))) (4) (M + m_1 + m_2 )(g/μ) Q3. Let vertical part of block M be smooth. Choose the correct alternative (1) There exist two limiting values for system to remain relatively at rest (2) For one unique value of F, the blocks m_1 and m_2 remain stationary with respect to block M (3) The blocks m_1 and m_2 cannot be in equilibrium for any value of F (4) There exists a range of mass M, for which system remains stationary

AblockofmassMisplacedonsmoothground.Itsuppersurfaceissmoothandverticalsurfaceisroughwithcoefficientoffrictionμ.Ablockofmassm1isplacedonitshorizontalsurfaceandtiedwithamasslessinextensiblestringpassingoversmoothpulley.Itsotherendisconnectedtoanotherblockofmassm2,whichtouchestheverticalsurfaceofblockM.NowahorizontalforceFstartsactingonit.Q1.Whichofthefollowingisincorrectaboutabovesystem?(1)ThereexistsavalueofFatwhichfrictionforceisequaltozero(2)WhenF=0,theblockscannotremainstationary(3)ThereexiststwolimitingvaluesofFatwhichtheblocksm1andm2willremainstationaryw.r.t.blockofmassM(4)Thelimitingfrictionbetweenm2andMisindependentofFQ2.Intheabovecase,letm1μm2begreaterthan1.ChoosetheincorrectvalueofFforwhichtheblocksm1andm2remainstationarywithrespecttoM(1)(M+m1+m2)m2gm1(2)m2(M+m1+m2)(m1μm2)g(3)(M+m1+m2)m2g(m1+μm2)(4)(M+m1+m2)gμQ3.LetverticalpartofblockMbesmooth.Choosethecorrectalternative(1)Thereexisttwolimitingvaluesforsystemtoremainrelativelyatrest(2)ForoneuniquevalueofF,theblocksm1andm2remainstationarywithrespecttoblockM(3)Theblocksm1andm2cannotbeinequilibriumforanyvalueofF(4)ThereexistsarangeofmassM,forwhichsystemremainsstationary

Question Number 21557    Answers: 0   Comments: 0

A man of mass 85 kg stands on a lift of mass 30 kg. When he pulls on the rope, he exerts a force of 400 N on the floor of the lift. Calculate acceleration of the lift. Given g = 10 m/s^2 .

Amanofmass85kgstandsonaliftofmass30kg.Whenhepullsontherope,heexertsaforceof400Nonthefloorofthelift.Calculateaccelerationofthelift.Giveng=10m/s2.

Question Number 21545    Answers: 0   Comments: 0

Question Number 21535    Answers: 0   Comments: 0

Which forces of attraction are responsible for liquefaction of H_2 ? (a) Coulombic forces (b) Dipole forces (c) Hydrogen bonding (d) Van der Waal′s forces.

WhichforcesofattractionareresponsibleforliquefactionofH2?(a)Coulombicforces(b)Dipoleforces(c)Hydrogenbonding(d)VanderWaalsforces.

Question Number 21516    Answers: 2   Comments: 0

A 5-kg body is suspended from a spring- balance, and an identical body is balanced on a pan of a physical balance. If both the balances are kept in an elevator, then what would happen in each case when the elevator is moving with an upward acceleration?

A5kgbodyissuspendedfromaspringbalance,andanidenticalbodyisbalancedonapanofaphysicalbalance.Ifboththebalancesarekeptinanelevator,thenwhatwouldhappenineachcasewhentheelevatorismovingwithanupwardacceleration?

Question Number 21486    Answers: 0   Comments: 0

Vapour pressure in a closed container can be changed by (1) Adding water vapours from outside at same temperature (2) Adding ice at same temperature (3) Adding water at same temperature (4) Increasing temperature

Vapourpressureinaclosedcontainercanbechangedby(1)Addingwatervapoursfromoutsideatsametemperature(2)Addingiceatsametemperature(3)Addingwateratsametemperature(4)Increasingtemperature

Question Number 21484    Answers: 0   Comments: 0

Positive deviation from ideal behaviour takes place because of (a) molecular interaction between atoms and PV/nRT > 1 (b) molecular interaction between atoms and PV/nRT < 1 (c) finite size of the atoms and PV/nRT > 1 (d) finite size of the atoms and PV/nRT < 1

Positivedeviationfromidealbehaviourtakesplacebecauseof(a)molecularinteractionbetweenatomsandPV/nRT>1(b)molecularinteractionbetweenatomsandPV/nRT<1(c)finitesizeoftheatomsandPV/nRT>1(d)finitesizeoftheatomsandPV/nRT<1

Question Number 21482    Answers: 0   Comments: 0

Question Number 21469    Answers: 1   Comments: 1

Three identical blocks, each having a mass M, are pushed by a force F on a frictionless table. What is the net force on the block A?

Threeidenticalblocks,eachhavingamassM,arepushedbyaforceFonafrictionlesstable.WhatisthenetforceontheblockA?

Question Number 21507    Answers: 1   Comments: 1

The length of an ideal spring increases by 0.1 cm when a body of 1 kg is suspended from it. If this spring is laid on a frictionless horizontal table and bodies of 1 kg each are suspended from its ends, then what will be the increase in its length?

Thelengthofanidealspringincreasesby0.1cmwhenabodyof1kgissuspendedfromit.Ifthisspringislaidonafrictionlesshorizontaltableandbodiesof1kgeacharesuspendedfromitsends,thenwhatwillbetheincreaseinitslength?

Question Number 21441    Answers: 1   Comments: 0

Find α in terms of θ using the equations: (i) u^2 sin^2 α = 2gd cos θ (ii) t = ((u cos α)/(g sin θ)) (iii) −d = ut sin α − ((gt^2 sin θ)/2)

Findαintermsofθusingtheequations:(i)u2sin2α=2gdcosθ(ii)t=ucosαgsinθ(iii)d=utsinαgt2sinθ2

Question Number 21412    Answers: 0   Comments: 0

The atomic masses of ′He′ and ′Ne′ are 4 and 20 a.m.u., respectively. The value of the de Broglie wavelength of ′He′ gas at −73°C is “M” times that of the de Broglie wavelength of ′Ne′ at 727°C ′M′ is

TheatomicmassesofHeandNeare4and20a.m.u.,respectively.ThevalueofthedeBrogliewavelengthofHegasat73°CisMtimesthatofthedeBrogliewavelengthofNeat727°CMis

Question Number 21411    Answers: 0   Comments: 0

The critical temperature of water is higher than that of O_2 because the H_2 O molecule has (a) fewer electrons than O_2 (b) two covalent bonds (c) V-shape (d) dipole moment.

ThecriticaltemperatureofwaterishigherthanthatofO2becausetheH2Omoleculehas(a)fewerelectronsthanO2(b)twocovalentbonds(c)Vshape(d)dipolemoment.

Question Number 21388    Answers: 0   Comments: 4

A block of mass m is connected with another block of mass 2m by a light spring. 2m is connected with a hanging mass 3m by an inextensible light string. At the time of release of block 3m, find tension in the string and acceleration of all the masses.

Ablockofmassmisconnectedwithanotherblockofmass2mbyalightspring.2misconnectedwithahangingmass3mbyaninextensiblelightstring.Atthetimeofreleaseofblock3m,findtensioninthestringandaccelerationofallthemasses.

Question Number 21377    Answers: 0   Comments: 0

Balls are dropped from the roof of a tower at a fixed interval of time. At the moment when 9th ball reaches the ground the nth ball is (3/4)th height of the tower. What is the value of n?

Ballsaredroppedfromtheroofofatoweratafixedintervaloftime.Atthemomentwhen9thballreachesthegroundthenthballis(3/4)thheightofthetower.Whatisthevalueofn?

Question Number 21295    Answers: 1   Comments: 0

For a particle performing uniform circular motion, angular momentum is constant in magnitude but direction keeps changing. Am I right or wrong?

Foraparticleperforminguniformcircularmotion,angularmomentumisconstantinmagnitudebutdirectionkeepschanging.AmIrightorwrong?

Question Number 21282    Answers: 0   Comments: 0

soit (u_n )_(n∈N^∗ ) une suite a termes positifs telle que: ∀n∈N^∗ ,Σ_(k=1) ^n u_k ^3 =(Σ_(k=1) ^n u_k )^2 montrer que ∀n∈N^∗ , u_n =n

soit(un)nNunesuiteatermespositifstelleque:nN,nk=1uk3=(nk=1uk)2montrerquenN,un=n

Question Number 21276    Answers: 1   Comments: 0

Question Number 21249    Answers: 0   Comments: 1

A particle slides down a frictionless parabolic (y = x^2 ) track (A − B − C) starting from rest at point A. Point B is at the vertex of parabola and point C is at a height less than that of point A. After C, the particle moves freely in air as a projectile. If the particle reaches highest point at P, then (a) KE at P = KE at B (b) height at P = height at A (c) total energy at P = total energy at A (d) time of travel from A to B = time of travel from B to P.

Aparticleslidesdownafrictionlessparabolic(y=x2)track(ABC)startingfromrestatpointA.PointBisatthevertexofparabolaandpointCisataheightlessthanthatofpointA.AfterC,theparticlemovesfreelyinairasaprojectile.IftheparticlereacheshighestpointatP,then(a)KEatP=KEatB(b)heightatP=heightatA(c)totalenergyatP=totalenergyatA(d)timeoftravelfromAtoB=timeoftravelfromBtoP.

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