Question and Answers Forum

OthersQuestion and Answers: Page 138

Question Number 18322 Answers: 1 Comments: 1

The pulley arrangements are identical. The mass of the rope is negligible. In (a), the mass m is lifted up by attaching a mass (2m) to the other end of the rope. In (b), m is lifted up by pulling the other end of the rope with a constant downward force F = 2mg. In which case, the acceleration of m is more?

$The pulley arrangements are identical .$ $The mass of the rope is negligible . In$ $(a), the mass m is lifted up by attaching$ $a mass (2 m) to the other end of the rope .$ $In (b), m is lifted up by pulling the$ $other end of the rope with a constant$ $downward force F = 2 m g . In which$ $case, the acceleration of m is more ?$

Question Number 18320 Answers: 1 Comments: 0

In a triangle ABC with fixed base BC, the vertex A moves such that cos B + cos C = 4 sin^2 (A/2) . If a, b and c denote the lengths of the sides of the triangle opposite to the angles A, B and C respectively, then (1) b + c = 4a (2) b + c = 2a (3) Locus of point A is an ellipse (4) Locus of point A is a pair of straight lines

$In a triangle A B C with fixed base B C,$ $the vertex A moves such that \cos B +$ $\cos C = 4 \sin^{2} \frac{A}{2} . If a, b and c denote$ $the lengths of the sides of the triangle$ $opposite to the angles A, B and C$ $respectively, then$ $(1) b + c = 4 a$ $(2) b + c = 2 a$ $(3) Locus of point A is an ellipse$ $(4) Locus of point A is a pair of straight$ $lines$

Question Number 18274 Answers: 1 Comments: 0

A balloon moves up vertically such that if a stone is projected with a horizontal velocity u relative to balloon, the stone always hits the ground at a fixed point at a distance ((2u^2 )/g) horizontally away from it. Find the height of the balloon as a function of time.

$A balloon moves up vertically such$ $that if a stone is projected with a$ $horizontal velocity u relative to balloon,$ $the stone always hits the ground at a$ $fixed point at a distance \frac{2 u^{2}}{g} horizontally$ $away from it . Find the height of the$ $balloon as a function of time .$

Question Number 18271 Answers: 0 Comments: 3

There are two parallel planes, each inclined to the horizontal at an angle θ. A particle is projected from a point mid way between the foot of the two planes so that it grazes one of the planes and strikes the other at right angle. Find the angle of projection of the projectile.

$There are two parallel planes, each$ $inclined to the horizontal at an angle θ .$ $A particle is projected from a point mid$ $way between the foot of the two planes$ $so that it grazes one of the planes and$ $strikes the other at right angle . Find$ $the angle of projection of the projectile .$

Question Number 18269 Answers: 0 Comments: 3

The flow velocity of a river increases linearly with the distance (r) from its bank and has its maximum value v_0 in the middle of the river. The velocity near the bank is zero. A boat which can move with speed u in still water moves in the river in such a way that it is always perpendicular to the flow of current. Find (i) The distance along the bank through which boat is carried away by the flow current, when the boat crosses the river. (ii) The equation of trajectory for the coordinate system shown. Assume that the swimmer starts from origin.

$The flow velocity of a river increases$ $linearly with the distance (r) from its$ $bank and has its maximum value v_{0} in$ $the middle of the river . The velocity$ $near the bank is zero . A boat which can$ $move with speed u in still water moves$ $in the river in such a way that it is$ $always perpendicular to the flow of$ $current . Find$ $(i) The distance along the bank through$ $which boat is carried away by the flow$ $current, when the boat crosses the$ $river .$ $(ii) The equation of trajectory for the$ $coordinate system shown . Assume$ $that the swimmer starts from origin .$

Question Number 18268 Answers: 1 Comments: 0

A balloon starts rising from the surface of earth. The ascension rate is constant and is equal to v_0 . Due to wind the balloon gathers horizontal velocity component v_x = ay, where a is a positive constant and y is the height of ascent. Find (i) The horizontal drift of the balloon x(y), (ii) The total, tangential and normal accelerations of the balloon.

$A balloon starts rising from the surface$ $of earth . The ascension rate is constant$ $and is equal to v_{0} . Due to wind the$ $balloon gathers horizontal velocity$ $component v_{x} = a y, where a is a positive$ $constant and y is the height of ascent .$ $Find$ $(i) The horizontal drift of the balloon$ $x (y),$ $(ii) The total, tangential and normal$ $accelerations of the balloon .$

Question Number 19654 Answers: 0 Comments: 3

Two swimmers leave point A on one bank of the river to reach point B lying right across the other bank. One of them crosses the river along the straight line AB while the other swims at right angle to the stream and then walks the distance that he has been carried away by the stream to get to point B. What was the velocity v of his walking if both swimmers reached the destination simultaneously? (The stream velocity v_0 = 2 km/h and the velocity v′ of each swimmer with respect to still water is 2.5 km/h).

$Two swimmers leave point A on one$ $bank of the river to reach point B lying$ $right across the other bank . One of$ $them crosses the river along the straight$ $line A B while the other swims at right$ $angle to the stream and then walks the$ $distance that he has been carried away$ $by the stream to get to point B . What$ $was the velocity v of his walking if both$ $swimmers reached the destination$ $simultaneously ? (The stream velocity$ $v_{0} = 2 km / h and the velocity v^{'} of each$ $swimmer with respect to still water is$ $2.5 km / h) .$

Question Number 18265 Answers: 0 Comments: 7

A particle is projected at an angle 60° with speed 10(√3) m/s from the point A as shown in the figure. At the same time the wedge is made to move with speed 10(√3) m/s toward right as shown in figure. Find the time after which particle will strike the wedge.

$A particle is projected at an angle 60 °$ $with speed 10 \sqrt{3} m / s from the point A$ $as shown in the figure . At the same$ $time the wedge is made to move with$ $speed 10 \sqrt{3} m / s toward right as shown$ $in figure . Find the time after which$ $particle will strike the wedge .$

Question Number 18264 Answers: 1 Comments: 0

A sky diver of mass m drops out with an initial velocity v_0 = 0. Find the law by which the sky diver′s speed varies before the parachute is opened if the drag is proportional to the sky diver′s speed. Also solve the problem when the sky diver′s initial velocity has horizontal component v_0 and vertical component zero.

$A sky diver of mass m drops out with$ $an initial velocity v_{0} = 0 . Find the law$ $by which the sky {diver}^{'} s speed varies$ $before the parachute is opened if the$ $drag is proportional to the sky {diver}^{'} s$ $speed . Also solve the problem when the$ $sky {diver}^{'} s initial velocity has horizontal$ $component v_{0} and vertical component$ $zero .$

Question Number 18262 Answers: 1 Comments: 2

A point P is located above an inclined plane. It is possible to reach the plane by sliding under gravity down a straight frictionless wire joining to some point P ′ on the plane. How should P ′ be chosen so as to minimize the time taken?

$A point P is located above an inclined$ $plane . It is possible to reach the plane$ $by sliding under gravity down a straight$ $frictionless wire joining to some point$ $P^{'} on the plane . How should P^{'} be$ $chosen so as to minimize the time$ $taken ?$

Question Number 18206 Answers: 0 Comments: 0

1+((1×3)/6)+((1×3×5)/(6×8))+...∞

$1 + \frac{1 \times 3}{6} + \frac{1 \times 3 \times 5}{6 \times 8} + . . . \infty$

Question Number 20973 Answers: 1 Comments: 1

A small solid spherical ball of high density is dropped in a viscous liquid. Its journey in the liquid is best described in the following figure by the curve

$A small solid spherical ball of high$ $density is dropped in a viscous liquid .$ $Its journey in the liquid is best described$ $in the following figure by the curve$

Question Number 20972 Answers: 0 Comments: 0

Boyle temperature is given by (1) T_B = (a/(Rb^2 )) (2) T_B = (a/(Rb)) (3) T_B = (a/(27b^2 )) (4) T_B = (b/(aR))

$Boyle temperature is given by$ $(1) T_{B} = \frac{a}{{Rb}^{2}}$ $(2) T_{B} = \frac{a}{Rb}$ $(3) T_{B} = \frac{a}{{27 b}^{2}}$ $(4) T_{B} = \frac{b}{aR}$

Question Number 20976 Answers: 0 Comments: 0

What would be the percentage composition by volume of a mixture of CO and CH_4 , whose 10.5 mL requires 9 mL oxygen for complete combustion?

$What would be the percentage$ $composition by volume of a mixture of$ $CO and {CH}_{4}, whose 10.5 mL requires$ $9 mL oxygen for complete combustion ?$

Question Number 18202 Answers: 1 Comments: 0

An open vessel at 27°C is heated until (3/5) parts of the air in it has been expelled. Assuming that the volume of the vessel remains constant, find the temperature to which the vessel has been heated.

$An open vessel at 27 ° C is heated until$ $\frac{3}{5} parts of the air in it has been expelled .$ $Assuming that the volume of the vessel$ $remains constant, find the temperature$ $to which the vessel has been heated .$

Question Number 18199 Answers: 0 Comments: 0

What is the equivalent weight of KH(IO_3 )_2 as an oxidant in presence of 4 (N) HCl when ICl becomes the reduced form? (K = 39, I = 127)

$What is the equivalent weight of$ $KH {({IO}_{3})}_{2} as an oxidant in presence of$ $4 (N) HCl when ICl becomes the$ $reduced form ? (K = 39, I = 127)$

Question Number 18198 Answers: 1 Comments: 0

Mixture X = 0.02 mol of [Co(NH_3 )_5 SO_4 ]Br and 0.02 mol of [Co(NH_3 )_5 Br]SO_4 was prepared in 2 litre of solution 1 litre of mixture X + excess AgNO_3 → Y 1 litre of mixture X + excess BaCl_2 → Z Number of moles of Y and Z are

$Mixture X = 0.02 mol of$ $[Co {({NH}_{3})}_{5} {SO}_{4}] Br and 0.02 mol of$ $[Co {({NH}_{3})}_{5} Br] {SO}_{4} was prepared in 2$ $litre of solution$ $1 litre of mixture X + excess {AgNO}_{3} \to Y$ $1 litre of mixture X + excess {BaCl}_{2} \to Z$ $Number of moles of Y and Z are$

Question Number 18197 Answers: 1 Comments: 0

Rearrange the following (I to IV) in the the order of increasing masses. I. 1 molecule of oxygen II. 1 atom of nitrogen III. 10^(10) g molecular weight of oxygen IV. 10^(−18) g atomic weight of copper

$Rearrange the following (I to IV) in the$ $the order of increasing masses .$ $I . 1 molecule of oxygen$ $II . 1 atom of nitrogen$ $III . 10^{10} g molecular weight of oxygen$ $IV . 10^{- 18} g atomic weight of copper$

Question Number 18186 Answers: 2 Comments: 0

3.92 g of ferrous ammonium sulphate are dissolved in 100 ml of water. 20 ml of this solution requires 18 ml of potassium permanganate during titration for complete oxidation. The weight of KMnO_4 present in one litre of the solution is

$3.92 g of ferrous ammonium sulphate$ $are dissolved in 100 ml of water . 20 ml$ $of this solution requires 18 ml of$ $potassium permanganate during$ $titration for complete oxidation . The$ $weight of {KMnO}_{4} present in one litre$ $of the solution is$

Question Number 18261 Answers: 1 Comments: 0

What is the maximum angle to the horizontal at which a stone can be thrown and always be moving away from the thrower?

$What is the maximum angle to the$ $horizontal at which a stone can be$ $thrown and always be moving away$ $from the thrower ?$

Question Number 18142 Answers: 1 Comments: 1

An object A is kept fixed at the point x = 3 m and y = 1.25 m on a plank P raised above the ground. At time t = 0, the plank starts moving along the x- direction with an acceleration 1.5 ms^(−2) . At the same instant a stone is projected from the origin with a velocity u^→ as shown. A stationary person on the ground observe the stone hitting the object during its downward motion at an angle of 45° with the horizontal. Take g = 10 m/s^2 and consider all motions in the x-y plane. 1. The time after which the stone hits the object is 2. The initial velocity (u^→ ) of the particle is

$An object A is kept fixed at the point$ $x = 3 m and y = 1.25 m on a plank P$ $raised above the ground . At time t = 0,$ $the plank starts moving along the x -$ $direction with an acceleration 1.5 {ms}^{- 2} .$ $At the same instant a stone is projected$ $from the origin with a velocity \vec{u} as$ $shown . A stationary person on the$ $ground observe the stone hitting the$ $object during its downward motion at$ $an angle of 45 ° with the horizontal .$ $Take g = 10 m / s^{2} and consider all$ $motions in the x - y plane .$ $1 . The time after which the stone hits$ $the object is$ $2 . The initial velocity (\vec{u}) of the$ $particle is$

Question Number 18140 Answers: 1 Comments: 0

From a tower of height H, a particle is thrown vertically upward with speed u. The time taken by the particle, to hit the ground, is n times that taken by it to reach the highest point of its path. The relation between H, u and n is (1) 2gH = n^2 u^2 (2) gH = (n − 2)^2 u^2 (3) 2gH = nu^2 (n − 2) (4) gH = (n − 2)u^2

$From a tower of height H, a particle is$ $thrown vertically upward with speed$ $u . The time taken by the particle, to$ $hit the ground, is n times that taken by$ $it to reach the highest point of its path .$ $The relation between H, u and n is$ $(1) 2 g H = n^{2} u^{2}$ $(2) g H = {(n - 2)}^{2} u^{2}$ $(3) 2 g H = {n u}^{2} (n - 2)$ $(4) g H = (n - 2) u^{2}$

Question Number 18131 Answers: 0 Comments: 3

A stone is projected from a point on the ground in such a direction so as to hit a bird on the top of a telegraph post of height h, and then attain a height 2h above the ground. If, at an instant of projection, the bird were to fly away horizontal with a uniform speed, find the ratio of the horizontal velocities of the bird and the stone, if the stone still hits the bird.

$A stone is projected from a point on the$ $ground in such a direction so as to hit a$ $bird on the top of a telegraph post of$ $height h, and then attain a height 2 h$ $above the ground . If, at an instant of$ $projection, the bird were to fly away$ $horizontal with a uniform speed, find$ $the ratio of the horizontal velocities of$ $the bird and the stone, if the stone still$ $hits the bird .$

Question Number 18107 Answers: 0 Comments: 0

The first and second ionization potentials of helium atoms are 24.58 eV and 54.4 eV per mole respectively. Calculate the energy in kJ required to produce 1 mole of He^(2+) ions.

$The first and second ionization$ $potentials of helium atoms are 24.58 eV$ $and 54.4 eV per mole respectively .$ $Calculate the energy in kJ required to$ $produce 1 mole of {He}^{2 +} ions .$

Question Number 18106 Answers: 0 Comments: 0

The ionization potential of hydrogen is 13.60 eV/mole. Calculate the energy in kJ required to produce 0.1 mole of H^+ ions. Given, 1 eV = 96.49 kJ mol^(−1) )

$The ionization potential of hydrogen is$ $13.60 eV / mole . Calculate the energy in$ $kJ required to produce 0.1 mole of H^{+}$ $ions . Given, 1 eV = 96.49 kJ {mol}^{- 1})$

Question Number 18095 Answers: 1 Comments: 0

A boy travelling in an open car moving on a levelled road with constant speed tosses a ball vertically up in the air and catches it back. Sketch the motion of the ball as observed by a boy standing on the footpath. Give explanation to support your diagram.

$A boy travelling in an open car moving$ $on a levelled road with constant speed$ $tosses a ball vertically up in the air and$ $catches it back . Sketch the motion of$ $the ball as observed by a boy standing$ $on the footpath . Give explanation to$ $support your diagram .$

Pg 133 Pg 134 Pg 135 Pg 136 Pg 137 Pg 138 Pg 139 Pg 140 Pg 141 Pg 142

Contact: info@tinkutara.com