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Question Number 171152 Answers: 1 Comments: 0

The average ages of three person is 27 years. Their ages are in the propor tion of 1:3:5. What is the age in years of the youngest one among them? Mastermind

$T h e a v e r a g e a g e s o f t h r e e p e r s o n i s$ $27 y e a r s . T h e i r a g e s a r e i n t h e p r o p o r$ $t i o n o f 1 : 3 : 5 . W h a t i s t h e a g e i n y e a r s$ $o f t h e y o u n g e s t o n e a m o n g t h e m ?$ $M a s t e r m i n d$

Question Number 171107 Answers: 0 Comments: 0

Please help lim_(x→−∞) (x−1)e^(x−1) −1=? lim_(x→+∞) (x−1)e^(x−1) −1=? g(x)=(x−1)e^(x−1) −1 g(x)′=?

$P l e a s e h e l p$ $l i \underset{x \to - \infty}{m} (x - 1) e^{x - 1} - 1 = ?$ $l i \underset{x \to + \infty}{m} (x - 1) e^{x - 1} - 1 = ?$ $g (x) = (x - 1) e^{x - 1} - 1$ $g {(x)}^{'} = ?$

Question Number 171094 Answers: 0 Comments: 0

prove that: 𝛀=Σ_(n=0) ^∞ ((((n!)^2 )/((2n)!)))^2 (2^(4n) /((2n+1)^3 ))=^? (7/2)𝛇(3)−πG G−Catalan′s constant

$prove that :$ $Ω = \underset{n = 0}{\sum^{\infty}} {(\frac{{(n!)}^{2}}{(2 n)!})}^{2} \frac{2^{4 n}}{{(2 n + 1)}^{3}} \overset{?}{=} \frac{7}{2} ζ (3) - π G$ $G - {Catalan}^{'} s constant$

Question Number 171032 Answers: 1 Comments: 0

Find the domain and range of the function, f(x)=((x^2 +2)/(2x+1)) Mastermind

$F i n d t h e d o m a i n a n d r a n g e o f t h e$ $f u n c t i o n, f (x) = \frac{x^{2} + 2}{2 x + 1}$ $M a s t e r m i n d$

Question Number 171025 Answers: 2 Comments: 0

Question Number 171038 Answers: 2 Comments: 0

Question Number 171009 Answers: 1 Comments: 0

Find the inverse, y^(−1) of the function y=x^3 +4. Mastermind

$F i n d t h e i n v e r s e, y^{- 1} o f t h e f u n c t i o n$ $y = x^{3} + 4 .$ $M a s t e r m i n d$

Question Number 171008 Answers: 0 Comments: 1

Find the maximum and minimum values of h(x)=(4/3)x^3 +(9/2)x^2 +5x+8. Mastermind

$F i n d t h e m a x i m u m a n d m i n i m u m$ $v a l u e s o f h (x) = \frac{4}{3} x^{3} + \frac{9}{2} x^{2} + 5 x + 8 .$ $M a s t e r m i n d$

Question Number 171006 Answers: 0 Comments: 1

Find the area enclosed by the curve y=4−3x^2 and the x−axis between x_1 =−1 and x_2 =1. Mastermind

$F i n d t h e a r e a e n c l o s e d b y t h e c u r v e$ $y = 4 - 3 x^{2} a n d t h e x - a x i s b e t w e e n$ $x_{1} = - 1 a n d x_{2} = 1 .$ $M a s t e r m i n d$

Question Number 171005 Answers: 0 Comments: 0

The distance S metre travelled in time t seconds by an object released from rest and allow to fall freely under the force of gravity is given by s(t)=4.5t^2 . find a) the average speed of the object during the time interval from 2 to 2.5 seconds. b) the instantaneous velocity of the object after 4 seconds. Mastermind

$T h e d i s t a n c e S m e t r e t r a v e l l e d i n t i m e$ $t s e c o n d s b y a n o b j e c t r e l e a s e d f r o m$ $r e s t a n d a l l o w t o f a l l f r e e l y u n d e r t h e$ $f o r c e o f g r a v i t y i s g i v e n b y s (t) = 4.5 t^{2} .$ $f i n d$ $a) t h e a v e r a g e s p e e d o f t h e o b j e c t$ $d u r i n g t h e t i m e i n t e r v a l f r o m 2 t o$ $2.5 s e c o n d s .$ $b) t h e i n s t a n t a n e o u s v e l o c i t y o f t h e$ $o b j e c t a f t e r 4 s e c o n d s .$ $M a s t e r m i n d$

Question Number 170997 Answers: 1 Comments: 0

Find the equation of the tangent to the curve x^2 +y^2 −4x+6y−12=0 at the point (2, 3). Mastermind

$F i n d t h e e q u a t i o n o f t h e t a n g e n t t o t h e$ $c u r v e x^{2} + y^{2} - 4 x + 6 y - 12 = 0 a t t h e$ $p o i n t (2, 3) .$ $M a s t e r m i n d$

Question Number 170996 Answers: 1 Comments: 0

Find the volume of the solid obtained by rotating about x−axis of the curve y=(√x) on the interval [0, 2]. Mastermind

$F i n d t h e v o l u m e o f t h e s o l i d o b t a i n e d$ $b y r o t a t i n g a b o u t x - a x i s o f t h e c u r v e$ $y = \sqrt{x} o n t h e i n t e r v a l [0, 2] .$ $M a s t e r m i n d$

Question Number 170995 Answers: 0 Comments: 1

Approximate sin46° by “differentials” Mastermind

$A p p r o x i m a t e s i n 46 ° b y ‘ ‘ {d i f f e r e n t i a l s}^{″}$ $M a s t e r m i n d$

Question Number 170994 Answers: 1 Comments: 0

Show that the function h(x)=x^5 −2x is an odd function Mastermind

$Show that the function h (x) = x^{5} - 2 x$ $is an odd function$ $Mastermind$

Question Number 170986 Answers: 1 Comments: 2

Question Number 170950 Answers: 0 Comments: 2

e^x =ln(x), Make x the subject of the formula moreover find the value of x

$e^{x} = \ln (x), Make x the subject of the$ $formula$ $moreover find the value of x$

Question Number 170948 Answers: 0 Comments: 3

A^x^x +Bx^x +C=R, Make x the subject of the formular

$A^{x^{x}} + {Bx}^{x} + C = R, Make x the subject$ $of the formular$

Question Number 170946 Answers: 1 Comments: 0

Solve for x : 3^x =2x+2 Mastermind

$Solve for x :$ $3^{x} = 2 x + 2$ $Mastermind$

Question Number 170910 Answers: 0 Comments: 0

Question Number 170906 Answers: 2 Comments: 0

Question Number 170781 Answers: 2 Comments: 0

(√((2−x))) = (2−x)^2 solve for x

$\sqrt{(2 - x)} = {(2 - x)}^{2} solve for x$

Question Number 170780 Answers: 1 Comments: 0

Question Number 170743 Answers: 0 Comments: 0

2. Uma soluca^ o tampao foi preparada misturarando 200ml NH_(3 ) 0,6 moles e 300ml de uma solucao de NH_3 Cl 0,2 moles P^(kh) =9,24 e log 2=0,3 a) Qual e o P^h desta solucao tampa^ o supondo-se um volume de 500ml? b)Qual sera o P^h depois de ser adicionado 0,2 molar de ion [H^− ] Dados n(CH_3 -CH_2 COOH)=0,02mok/l=0,02M Ka=1,3∙10^(−5) n(CH_3 −CH_2 -COONa)=0,015mol/l=0,015M V=1l log 2=0,3 log 0,11 P^h =? 1°Passo 2°Passo P^(ka) =−log Ka P^h =P^(ka) +log(([Base])/([Acido])) P^(ka) =−log 1,3∙10^(−5) ? P^h =4,89+log(([0,02])/([0,015])) P^(ka) =(−5+0,11) P^h =4,89+log1,3 P^(ka) =5−11 P^h =4,89+0,11 P^(ka) =4,49 P^h =5 3°Passo P^h =P^h +log(([Basica])/([Acida])) P^h =4,89+log(([0,02])/([0,025])) P^h =4,89+log0,8 P^h =4,89+0,096 P^h =4,986≈5

$2 . Uma soluc \overset{}{a o} tampao foi preparada misturarando 200 m l {NH}_{3} 0, 6 m o l e s$ $e 300 m l d e u m a s o l u c a o d e {NH}_{3} C l 0, 2 m o l e s P^{kh} = 9, 24 e \log 2 = 0, 3$ $a) Q u a l e o P^{h} desta solucao tamp \overset{}{a o} supondo - s e u m v o l u m e d e 500 m l ?$ $b) Q u a l s e r a o P^{h} d e p o i s d e s e r a d i c i o n a d o 0, 2 m o l a r d e i o n [H^{-}]$ $Dados$ $n ({CH}_{3} - {CH}_{2} COOH) = 0, 02 m o k / l = 0, 02 M$ $K a = 1, 3 \cdot 10^{- 5}$ $n ({CH}_{3} - {CH}_{2} - COONa) = 0, 015 m o l / l = 0, 015 M$ $V = 1 l$ $\log 2 = 0, 3$ $\log 0, 11$ $P^{h} = ?$ $1 ° Passo 2 ° Passo$ $P^{ka} = - \log Ka P^{h} = P^{ka} + \log \frac{[Base]}{[Acido]}$ $P^{ka} = - \log 1, 3 \cdot 10^{- 5} ? P^{h} = 4, 89 + \log \frac{[0, 02]}{[0, 015]}$ $P^{ka} = (- 5 + 0, 11) P^{h} = 4, 89 + \log 1, 3$ $P^{ka} = 5 - 11 P^{h} = 4, 89 + 0, 11$ $P^{ka} = 4, 49 P^{h} = 5$ $3 ° Passo$ $P^{h} = P^{h} + \log \frac{[Basica]}{[Acida]}$ $P^{h} = 4, 89 + \log \frac{[0, 02]}{[0, 025]}$ $P^{h} = 4, 89 + \log 0, 8$ $P^{h} = 4, 89 + 0, 096$ $P^{h} = 4, 986 \approx 5$

Question Number 170673 Answers: 0 Comments: 2

Question Number 170659 Answers: 0 Comments: 0

c≥0 (U_n )_(n≥1) U_1 =1 U_(n+1) =(√(U_n +cn)) show that U_n ≤α(√n) determine α

$c ⩾ 0 {(U_{n})}_{n ⩾ 1} U_{1} = 1$ $U_{n + 1} = \sqrt{U_{n} + c n}$ $s h o w t h a t U_{n} ⩽ α \sqrt{n}$ $d e t e r m i n e α$

Question Number 170650 Answers: 1 Comments: 0

Tom bought a computer for 15% off from the list price of P dollars. If the sales tax was 8%, how much did he pay for the computer including sales tax?

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