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Question Number 140240 Answers: 0 Comments: 0

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Question Number 139975 Answers: 2 Comments: 0

∫_0 ^∞ (cos(x)−(1/((1+x^2 ))))(dx/x)=−γ

$\int_{0}^{\infty} (c o s (x) - \frac{1}{(1 + x^{2})}) \frac{d x}{x} = - γ$

Question Number 139950 Answers: 1 Comments: 0

Question Number 139778 Answers: 2 Comments: 0

prove that the absolute valje of z1+z2<=absolute value of z1+absolute value of z2

$p r o v e t h a t t h e a b s o l u t e v a l j e o f z 1 + z 2 <= a b s o l u t e v a l u e o f z 1 + a b s o l u t e v a l u e o f z 2$

Question Number 139619 Answers: 1 Comments: 0

Question Number 139618 Answers: 1 Comments: 0

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Question Number 139489 Answers: 0 Comments: 0

^• I am uncomcofortable and so is my writer. ^• My writer sometimes regrets after writing me and wants to delete me. WHO AM I ? ^■ I am an answer of some question of this forum WITHOUT ANY FEEDBACK OF THE QUESTIONER !

$^{∙} I a m u n c o m c o f o r t a b l e a n d s o$ $i s m y w r i t e r .$ $^{∙} M y w r i t e r s o m e t i m e s r e g r e t s$ $a f t e r w r i t i n g m e a n d w a n t s$ $t o d e l e t e m e .$ $\underset{―}{WHO AM I ?}$ $^{◼} I a m a n a n s w e r o f s o m e$ $q u e s t i o n o f t h i s f o r u m$ $W I T H O U T A N Y F E E D B A C K$ $O F T H E Q U E S T I O N E R!$

Question Number 139481 Answers: 0 Comments: 0

1+(π^6 /(27.6!))+(π^(12) /(27^2 .12!))+(π^(18) /(27^3 .18!))+...=((e^(π/( (√a))) +e^(−(π/( (√a)))) )/(2a)) Find a

$1 + \frac{π^{6}}{27.6!} + \frac{π^{12}}{27^{2} . 12!} + \frac{π^{18}}{27^{3} . 18!} + . . . = \frac{e^{\frac{π}{\sqrt{a}}} + e^{- \frac{π}{\sqrt{a}}}}{2 a}$ $F i n d a$

Question Number 139390 Answers: 0 Comments: 0

a uniform pole 30m and weight 40kg is carried at P by John and Ama 8m away from Q. Find the distance from P where a mass of 20kg should be attached so that Amas support is twice that of John if tbe system is in equilibrim

$a u n i f o r m p o l e 30 m a n d w e i g h t 40 k g i s c a r r i e d a t P b y J o h n a n d A m a 8 m a w a y f r o m Q . F i n d t h e d i s t a n c e f r o m P w h e r e a m a s s o f 20 k g s h o u l d b e a t t a c h e d s o t h a t A m a s s u p p o r t i s t w i c e t h a t o f J o h n i f t b e s y s t e m i s i n e q u i l i b r i m$