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Question Number 137750    Answers: 0   Comments: 2

Question Number 137746    Answers: 1   Comments: 0

Question Number 137645    Answers: 1   Comments: 0

The sum of the squares of two consecutive odd numbers is 130. Find the larger number.

Thesumofthesquaresoftwoconsecutiveoddnumbersis130.Findthelargernumber.

Question Number 137641    Answers: 1   Comments: 0

Question Number 137637    Answers: 0   Comments: 0

Prove or disprove ((cos(1+(1/( (√3))))𝛑)/1^2 )+((cos(1+(1/( (√3))))2π)/2^2 )+((cos(1+(1/( (√3))))3π)/3^2 )+...=0

Proveordisprovecos(1+13)π12+cos(1+13)2π22+cos(1+13)3π32+...=0

Question Number 137634    Answers: 1   Comments: 0

x=2^(p ) and y=2^(q ) . Evaluate in terms of x and/ or y (i)2^(p+q) (ii) 2^(2q ) (iii) 2^(p−1)

x=2pandy=2q.Evaluateintermsofxand/ory(i)2p+q(ii)22q(iii)2p1

Question Number 137618    Answers: 1   Comments: 2

Question Number 137598    Answers: 0   Comments: 0

Question Number 137545    Answers: 0   Comments: 0

Question Number 137528    Answers: 3   Comments: 1

Question Number 137437    Answers: 2   Comments: 0

Question Number 137403    Answers: 1   Comments: 1

Question Number 137384    Answers: 0   Comments: 4

Question Number 137353    Answers: 1   Comments: 0

If 75% of 68 is the same as 85% of n, find n.

If75%of68isthesameas85%ofn,findn.

Question Number 137332    Answers: 0   Comments: 0

Question Number 137316    Answers: 0   Comments: 0

An alternating current after passing through rectifire has the form i=I_0 sinx for 0≤x≤π =0 for π≤x≤2π where I_0 is the maximum current and period is 2π.express i is a fourire series and evaluate (1/(1.3))+(1/(3.5))+(1/(5.7))+.........∞

Analternatingcurrentafterpassingthroughrectifirehastheformi=I0sinxfor0xπ=0forπx2πwhereI0isthemaximumcurrentandperiodis2π.expressiisafourireseriesandevaluate11.3+13.5+15.7+.........

Question Number 137252    Answers: 1   Comments: 0

Decompose the function P(x) = ((x^4 +2x^3 +6x^2 +20x+6)/(x^3 +x^2 +x)) in partial fractions.

DecomposethefunctionP(x)=x4+2x3+6x2+20x+6x3+x2+xinpartialfractions.

Question Number 137191    Answers: 0   Comments: 0

Some useful approximations of sine function sin((π/7))=((96)/(221)) sin((π/9))=((128)/(373)) sin((π/(11)))=((32)/(113)) ... I am counting more ..thanking you!

Someusefulapproximationsofsinefunctionsin(π7)=96221sin(π9)=128373sin(π11)=32113...Iamcountingmore..thankingyou!

Question Number 136995    Answers: 0   Comments: 0

1−(((1.1.3)/(2.3.4)))(1/(1!))+(((3.3.7)/(2^2 .3^2 .4^2 )))(1/(2!))−(((5.7.10)/(2^3 .3^3 .4^3 )))(1/(3!))−....

1(1.1.32.3.4)11!+(3.3.722.32.42)12!(5.7.1023.33.43)13!....

Question Number 137016    Answers: 1   Comments: 0

Question Number 136950    Answers: 2   Comments: 0

Question Number 136930    Answers: 0   Comments: 6

Question Number 136899    Answers: 2   Comments: 0

Question Number 136892    Answers: 1   Comments: 0

∫(d^2 y/dx^2 )dy

d2ydx2dy

Question Number 136885    Answers: 1   Comments: 0

Question Number 136850    Answers: 0   Comments: 1

Σ_(n=−∞) ^∞ a^((n(n+1))/2) b^((n(n−1))/2) =1+(√((2a^2 )/π))∫_0 ^∞ e^(−t^2 /2) (((1−a(√(ab)) cosh((√(log(ab))) t))/(a^3 b−2a(√(ab )) cosh((√(log(ab))) t))))dt

n=an(n+1)2bn(n1)2=1+2a2π0et2/2(1aabcosh(log(ab)t)a3b2aabcosh(log(ab)t))dt

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