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Question Number 136899 Answers: 2 Comments: 0

Question Number 136892 Answers: 1 Comments: 0

∫(d^2 y/dx^2 )dy

$\int \frac{d^{2} y}{{d x}^{2}} d y$

Question Number 136885 Answers: 1 Comments: 0

Question Number 136850 Answers: 0 Comments: 1

Σ_(n=−∞) ^∞ a^((n(n+1))/2) b^((n(n−1))/2) =1+(√((2a^2 )/π))∫_0 ^∞ e^(−t^2 /2) (((1−a(√(ab)) cosh((√(log(ab))) t))/(a^3 b−2a(√(ab )) cosh((√(log(ab))) t))))dt

$\underset{n = - \infty}{\sum^{\infty}} a^{\frac{n (n + 1)}{2}} b^{\frac{n (n - 1)}{2}} = 1 + \sqrt{\frac{2 a^{2}}{π}} \int_{0}^{\infty} e^{- t^{2} / 2} (\frac{1 - a \sqrt{a b} c o s h (\sqrt{l o g (a b)} t)}{a^{3} b - 2 a \sqrt{a b} c o s h (\sqrt{l o g (a b)} t)}) d t$

Question Number 136826 Answers: 0 Comments: 0

Question Number 136823 Answers: 0 Comments: 0

Question Number 136799 Answers: 0 Comments: 0

∫_0 ^1 Π_(n=1) ^∞ (1−q^n )dq

$\int_{0}^{1} \underset{n = 1}{\prod^{\infty}} (1 - q^{n}) d q$

Question Number 136761 Answers: 1 Comments: 1

Question Number 136760 Answers: 1 Comments: 0

Question Number 136757 Answers: 1 Comments: 0

1+((1/2))^2 (1/(2.1!))+(((1.3)/2^2 ))^2 (1/(2^2 .2!))+(((1.3.5)/2^3 )).(1/(2^3 .3!))+....=(((Γ((1/4)))/((2π^3 )^(1/4) )))^2

$1 + {(\frac{1}{2})}^{2} \frac{1}{2.1!} + {(\frac{1.3}{2^{2}})}^{2} \frac{1}{2^{2} . 2!} + (\frac{1.3.5}{2^{3}}) . \frac{1}{2^{3} . 3!} + . . . . = {(\frac{Γ (\frac{1}{4})}{{(2 π^{3})}^{1 / 4}})}^{2}$

Question Number 136661 Answers: 0 Comments: 0

∫_0 ^1 (1−x)^(−(7/8)) (1+x)^(−(1/(16))) dx

$\int_{0}^{1} {(1 - x)}^{- \frac{7}{8}} {(1 + x)}^{- \frac{1}{16}} d x$

Question Number 136593 Answers: 1 Comments: 0

Question Number 136520 Answers: 3 Comments: 1

Question Number 136519 Answers: 1 Comments: 0

1−((1/2))^(2k) +(((1.3)/(2.4)))^(2k) −(((1.3.5)/(2.4.6)))^(2k) +(((1.3.5.7)/(2.4.6.8)))^(2k) −.... Find the general form

$1 - {(\frac{1}{2})}^{2 k} + {(\frac{1.3}{2.4})}^{2 k} - {(\frac{1.3.5}{2.4.6})}^{2 k} + {(\frac{1.3.5.7}{2.4.6.8})}^{2 k} - . . . .$ $F i n d t h e g e n e r a l f o r m$

Question Number 136420 Answers: 2 Comments: 0

Σ_(n=1) ^∞ ((sin(2n+1)θ)/((2n+1)^2 ))=(θ/2)log(2)+sinθ((log(sinθ))/4) _2 F_1 ((1/2),(1/2);(3/2);sin^2 θ)+((sinθ)/(16)) _2 F_1 ((1/2),(1/2),(1/2);(3/2);(3/2);sin^2 θ) Prove or disprove 0<θ<π

$\underset{n = 1}{\sum^{\infty}} \frac{s i n (2 n + 1) θ}{{(2 n + 1)}^{2}} = \frac{θ}{2} l o g (2) + s i n θ \frac{l o g (s i n θ)}{4}_{2} F_{1} (\frac{1}{2}, \frac{1}{2}; \frac{3}{2}; {s i n}^{2} θ) + \frac{s i n θ}{16}_{2} F_{1} (\frac{1}{2}, \frac{1}{2}, \frac{1}{2}; \frac{3}{2}; \frac{3}{2}; {s i n}^{2} θ)$ $P r o v e o r d i s p r o v e 0 < θ < π$

Question Number 136105 Answers: 0 Comments: 4

Question Number 136104 Answers: 0 Comments: 0

((cos(1+(√((43)/3)))π)/1^2 )+((cos(1+(√((43)/3)))2π)/2^2 )+((cos(1+(√((43)/3)))3π)/3^2 )+...=aπ Find a

$\frac{c o s (1 + \sqrt{\frac{43}{3}}) π}{1^{2}} + \frac{c o s (1 + \sqrt{\frac{43}{3}}) 2 π}{2^{2}} + \frac{c o s (1 + \sqrt{\frac{43}{3}}) 3 π}{3^{2}} + . . . = a π$ $F i n d a$

Question Number 136070 Answers: 1 Comments: 0

((sin((√2)))/1^3 )+((sin(2(√2)))/2^3 )+((sin(3(√2)))/3^3 )+...=((π^b +1)/( a(√b)))−(π/b) Find a−b

$\frac{s i n (\sqrt{2})}{1^{3}} + \frac{s i n (2 \sqrt{2})}{2^{3}} + \frac{s i n (3 \sqrt{2})}{3^{3}} + . . . = \frac{π^{b} + 1}{a \sqrt{b}} - \frac{π}{b}$ $F i n d a - b$

Question Number 136110 Answers: 0 Comments: 1

An engine is pumping water from a well 25m deep. It discharges 0.4 m^3 of water each second with a velocity of 12 ms^(−1) . Find the power of the pump given that the density of water is 1000 kg m^(−3) . take g = 10 ms^(−2)

$An engine is pumping water from a well 25 m deep . It discharges$ $0.4 m^{3} of water each second with a velocity of 12 {ms}^{- 1} . Find the$ $power of the pump given that the density of water is 1000 kg m^{- 3} .$ $take g = 10 {ms}^{- 2}$

Question Number 135976 Answers: 1 Comments: 0

Question Number 135906 Answers: 1 Comments: 0

Edit: this is already fixed. Therefore this thread is closed... There′s a glitch! Whenever you backspace from a line to delete it, you′ll end up directly in front of the first thing you typed, whatever it is. Also, is there a way for this app to run in portrait orrentation on tablets? Because I can′t seem to get it to rotate to that mode. I saw in your screenshots on the Google Play page that it was possible, but I can′t get it to work. I would perfer editing in that orrentation over the landscape rotation.

$E d i t : t h i s i s a l r e a d y f i x e d . T h e r e f o r e t h i s t h r e a d i s c l o s e d . . .$ ${There}^{'} s a glitch!$ $Whenever you backspace from a line to delete it, {you}^{'} ll end up directly in front of the first thing you typed,$ $whatever it is .$ $Also, is there a way for this app to run in portrait orrentation on tablets ? Because I {can}^{'} t seem to get it to rotate$ $to that mode . I saw in your screenshots on the Google Play page that it was possible, but I {can}^{'} t get it to work .$ $I would perfer editing in that orrentation over the landscape rotation .$

Question Number 135884 Answers: 1 Comments: 0

Σ_(n=1) ^∞ (H_n ^((7)) /n^2 )−(H_n ^((7)) /((n+1)^2 )) Σ_(k=1) ^n (1/k^m )=H_n ^((m))

$\underset{n = 1}{\sum^{\infty}} \frac{H_{n}^{(7)}}{n^{2}} - \frac{H_{n}^{(7)}}{{(n + 1)}^{2}}$ $\underset{k = 1}{\sum^{n}} \frac{1}{k^{m}} = H_{n}^{(m)}$

Question Number 135808 Answers: 0 Comments: 0

Question Number 135798 Answers: 0 Comments: 3

Question Number 135757 Answers: 1 Comments: 4

((1.1)/2)+(((1+(1/2))1)/2^2 )+(((1+(1/2)+(1/3))2)/2^3 )+(((1+(1/2)+(1/3)+(1/4))3)/2^4 )+(((1+(1/2)+(1/3)+(1/4)+(1/5))5)/2^5 )+...

$\frac{1.1}{2} + \frac{(1 + \frac{1}{2}) 1}{2^{2}} + \frac{(1 + \frac{1}{2} + \frac{1}{3}) 2}{2^{3}} + \frac{(1 + \frac{1}{2} + \frac{1}{3} + \frac{1}{4}) 3}{2^{4}} + \frac{(1 + \frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{5}) 5}{2^{5}} + . . .$

Question Number 135653 Answers: 1 Comments: 9

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