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Question Number 127293    Answers: 0   Comments: 0

Σ_(n=1) ^∞ ((coth(n))/n^3 )

n=1coth(n)n3

Question Number 127187    Answers: 0   Comments: 1

1−5((1/2))^3 +9((1/2).(3/4))^3 −13((1/2).(3/4).(5/6))^3 +..=(2/π) (prove)

15(12)3+9(12.34)313(12.34.56)3+..=2π(prove)

Question Number 127186    Answers: 0   Comments: 1

∫_0 ^a e^(−x^2 ) dx=((√π)/2)−(e^(−a^2 ) /(2a+(1/(a+(2/(2a+(3/(a+(4/(2a+...)))))))))) (Prove)

0aex2dx=π2ea22a+1a+22a+3a+42a+...(Prove)

Question Number 127080    Answers: 0   Comments: 1

Σ_(n=1) ^∞ (1/(e^(−φn) +((e^(2πn) −e^(−2φn) )/(2e^(−φn) +((e^(2πn) −e^(−2φn) )/(2e^(−φn) +((e^(2πn) −e^(−2φn) )/(2e^(−2φn) ...))))))))

n=11eϕn+e2πne2ϕn2eϕn+e2πne2ϕn2eϕn+e2πne2ϕn2e2ϕn...

Question Number 127004    Answers: 0   Comments: 1

Question Number 126977    Answers: 1   Comments: 1

Σ_(n=1) ^∞ (n^7 /7^n )

n=1n77n

Question Number 126934    Answers: 1   Comments: 3

(1/(1!))+((1!^2 )/(3!))+((2!^2 )/(5!))+((3!^2 )/(7!))+((4!^2 )/(9!))+....

11!+1!23!+2!25!+3!27!+4!29!+....

Question Number 126913    Answers: 1   Comments: 1

to Tinku tara equation editor is not available in playstore now...pls check..i suggested a few students to dowmload it

toTinkutaraequationeditorisnotavailableinplaystorenow...plscheck..isuggestedafewstudentstodowmloadit

Question Number 126907    Answers: 1   Comments: 0

Merry christmas !! 🎅🤶☃️🌄🎄🦌 🔔🔔🔔🔔🔔🔔🔔🔔🔔 🎄🎄🎄🎄🎄🎄🎄🎄 ∫_0 ^(1/2) ((tanh^(−1) x)/( (x)^(1/5) ))dx

Merrychristmas!!🎅🤶☃️🌄🎄🦌 🔔🔔🔔🔔🔔🔔🔔🔔🔔 🎄🎄🎄🎄🎄🎄🎄🎄 012tanh1xx5dx

Question Number 126780    Answers: 1   Comments: 1

Question Number 126704    Answers: 0   Comments: 0

((e^π −1)/(e^π +1))=(π/(2+(π^2 /(6+(π^2 /(10+(π^2 /(14+....))))))))

eπ1eπ+1=π2+π26+π210+π214+....

Question Number 192126    Answers: 2   Comments: 1

prove that ∣z∣ > ((∣Re(z)∣ +∣Im(z)∣)/2) , ∀z∈C

provethatz>Re(z)+Im(z)2,zC

Question Number 126669    Answers: 1   Comments: 2

Σ_(n=1) ^∞ (H_n ^2 /n^4 )

n=1Hn2n4

Question Number 126632    Answers: 2   Comments: 1

Question Number 126400    Answers: 1   Comments: 5

If a_n =6^n +8^n find (a_(1991) /(49)).

Ifan=6n+8nfinda199149.

Question Number 126200    Answers: 0   Comments: 3

(1/1^2 )−(1/2^3 )+(1/3^5 )−(1/4^7 )+(1/5^(11) )−(1/6^(13) )+....

112123+135147+15111613+....

Question Number 126092    Answers: 2   Comments: 0

A particle starts from rest at time t = 0 and moves in a straightline with variable acceleration a m/s^2 where a = (t/5) , 0 ≤ t ≤ 5 , a = (t/5) + ((10)/t^2 ) , t ≥ 5, t being measured in seconds. Show that the velocity is 22(1/2) m/s when t = 5 and 11 m/s when t = 10. Show also that the distance travelled by the particle in the first 10 seconds is (43(1/3)−10 ln 2) m.

Aparticlestartsfromrestattimet=0andmovesinastraightlinewithvariableaccelerationam/s2wherea=t5,0t5,a=t5+10t2,t5,tbeingmeasuredinseconds.Showthatthevelocityis2212m/swhent=5and11m/swhent=10.Showalsothatthedistancetravelledbytheparticleinthefirst10secondsis(431310ln2)m.

Question Number 125994    Answers: 1   Comments: 0

((Σ_(n=0) ^∞ e^(−n^2 ) )/(Σ_(n=0) ^∞ e^(−2n^2 ) ))

n=0en2n=0e2n2

Question Number 127492    Answers: 0   Comments: 0

((i!)/(π!)) (Exact form)

i!π!(Exactform)

Question Number 125939    Answers: 0   Comments: 0

∫_0 ^1 ((cos2x−tanx.cot(tanx))/(sin2x−tan(tanx)log(cos^2 x)))dx

01cos2xtanx.cot(tanx)sin2xtan(tanx)log(cos2x)dx

Question Number 125884    Answers: 0   Comments: 0

Σ_(n=0) ^∞ ((((√5)−2)^n (((2n)),(n) ))/(((2n+1)(((√5)+(1/( (√5))))^(n+(1/2)) +((√5)−(1/( (√5))))^(n−(1/2)) ))))

n=0(52)n(2nn)((2n+1)((5+15)n+12+(515)n12))

Question Number 125857    Answers: 1   Comments: 0

1+4((1/2))^7 +7(((1.3)/(2.4)))^7 +10(((1.3.5)/(2.4.6)))^7 +...

1+4(12)7+7(1.32.4)7+10(1.3.52.4.6)7+...

Question Number 125781    Answers: 0   Comments: 0

∫_0 ^∞ ((√x)/(1−x^2 )).(1/(e^(2πx) −1))dx

0x1x2.1e2πx1dx

Question Number 125708    Answers: 1   Comments: 0

∫_0 ^∞ ((1−tanhx)/( ((tanhx))^(1/5) ))dx

01tanhxtanhx5dx

Question Number 125652    Answers: 0   Comments: 0

Question Number 125585    Answers: 0   Comments: 5

((((1/(1!)))^2 −((1/(2!)))^2 +((1/(3!)))^2 −((1/(4!)))^2 +... )/(((1/(1!)))^2 +((1/(2!)))^2 +((1/(3!)))^2 +......))

(11!)2(12!)2+(13!)2(14!)2+...(11!)2+(12!)2+(13!)2+......

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