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Question Number 86140 Answers: 0 Comments: 1

Question Number 86132 Answers: 1 Comments: 0

∫x^3 sin(2x^2 +6)^5 dx

$\int x^{3} s i n {(2 x^{2} + 6)}^{5} d x$

Question Number 86128 Answers: 1 Comments: 0

⌊2x−(1/2)⌋=⌊∣x∣−(1/2)⌋=2x−2

$⌊ 2 x - \frac{1}{2} ⌋ = ⌊ ∣ x ∣ - \frac{1}{2} ⌋ = 2 x - 2$

Question Number 86116 Answers: 0 Comments: 1

lim_(x→∞) ((tanx)/x)

$\lim_{x \to \infty} \frac{t a n x}{x}$

Question Number 86062 Answers: 2 Comments: 1

∫((√(x^2 −25))/x)dx

$\int \frac{\sqrt{x^{2} - 25}}{x} d x$

Question Number 85982 Answers: 0 Comments: 2

A primitive of the function defned by f(x) = x −1 + (1/(x+1)) is A. F(x) = (x^2 /2) −x + ln(x + 1) B. F(x) = (x^2 /2) + ln(x−1) C. F(x) = (x^2 /2)−x + ln(1−x) D. F(x) = −x + ln(x−1)

$A primitive of the function defned by f (x) = x - 1 + \frac{1}{x + 1} is$ $A . F (x) = \frac{x^{2}}{2} - x + \ln (x + 1) B . F (x) = \frac{x^{2}}{2} + \ln (x - 1)$ $C . F (x) = \frac{x^{2}}{2} - x + \ln (1 - x) D . F (x) = - x + \ln (x - 1)$

Question Number 85888 Answers: 0 Comments: 5

i−∫_0 ^5 (x+[2x])^([(x/3)]) dx ii−∫_0 ^3 (z−{z})^([z]) dz

$i - \int_{0}^{5} {(x + [2 x])}^{[\frac{x}{3}]} d x$ $i i - \int_{0}^{3} {(z - {z})}^{[z]} d z$

Question Number 85872 Answers: 1 Comments: 1

∫cos^(2020) x dx = ?

$\int \cos^{2020} x dx = ?$

Question Number 85858 Answers: 0 Comments: 0

Is a matrix A^T A always positive definite?

$Is a matrix$ $A^{T} A always positive definite ?$

Question Number 85698 Answers: 0 Comments: 0

please any recommendation of a youtube video on General conics??

$please any recommendation of a youtube video$ $on General conics ? ?$

Question Number 85676 Answers: 0 Comments: 15

∫ _0 ^∞ (dx/((x+(√(1+x^2 )))^2 )) let x = tan t ⇒dx=sec^2 t dt ∫_0 ^(π/2) ((sec^2 t dt)/((tan t+sec t)^2 )) = ∫_0 ^(π/2) (dt/((sin t+1)^2 )) = ∫_0 ^(π/2) (dt/((cos (1/2)t+sin (1/2)t)^4 )) = ∫_0 ^(π/2) (dt/(4cos^4 ((1/2)t−(π/4)))) = (1/4)∫_0 ^(π/2) sec^4 ((1/2)t−(π/4)) dt [ let (1/2)t−(π/4)= u] = (1/4)∫_(−(π/4)) ^0 sec^4 u ×2du =(1/2)∫ _(−(π/4)) ^0 (tan^2 u+1) d(tan u) = (1/2) [(1/3)tan^3 u + tan u ]_(−(π/4)) ^0 = (1/2) [ 0−(−(1/3)−1)]= (2/3)

$\int \underset{0}{\overset{\infty}{}} \frac{d x}{{(x + \sqrt{1 + x^{2}})}^{2}}$ $l e t x = \tan t \Rightarrow d x = \sec^{2} t d t$ $\underset{0}{\int^{\frac{π}{2}}} \frac{\sec^{2} t d t}{{(\tan t + \sec t)}^{2}} =$ $\underset{0}{\int^{\frac{π}{2}}} \frac{d t}{{(\sin t + 1)}^{2}} = \underset{0}{\int^{\frac{π}{2}}} \frac{d t}{{(\cos \frac{1}{2} t + \sin \frac{1}{2} t)}^{4}}$ $= \underset{0}{\int^{\frac{π}{2}}} \frac{d t}{{4 \cos}^{4} (\frac{1}{2} t - \frac{π}{4})}$ $= \frac{1}{4} \underset{0}{\int^{\frac{π}{2}}} \sec^{4} (\frac{1}{2} t - \frac{π}{4}) d t$ $[l e t \frac{1}{2} t - \frac{π}{4} = u]$ $= \frac{1}{4} \underset{- \frac{π}{4}}{\int^{0}} \sec^{4} u \times 2 d u$ $= \frac{1}{2} \int \underset{- \frac{π}{4}}{\overset{0}{}} (\tan^{2} u + 1) d (\tan u)$ $= \frac{1}{2} {[\frac{1}{3} \tan^{3} u + \tan u]}_{- \frac{π}{4}}^{0}$ $= \frac{1}{2} [0 - (- \frac{1}{3} - 1)] = \frac{2}{3}$

Question Number 85580 Answers: 0 Comments: 0

Solve: (D^2 +2D+1)y= x cos x

$Solve :$ $(D^{2} + 2 D + 1) y = x \cos x$

Question Number 85354 Answers: 0 Comments: 0

∫x(sin(cos(x)))^(x−1) dx

$\int x {(s i n (c o s (x)))}^{x - 1} d x$

Question Number 85286 Answers: 0 Comments: 2

Question Number 85279 Answers: 3 Comments: 0

who can help write out the mechanism for the reaction C_6 H_6 →_(HNO_3 ) ^(H_2 SO_4 ) C_6 H_5 NO_2

$who can help write out the mechanism for the$ $reaction$ $C_{6} H_{6} \underset{{HNO}_{3}}{\overset{H_{2} {SO}_{4}}{\to}} C_{6} H_{5} {NO}_{2}$

Question Number 85262 Answers: 1 Comments: 6

find the centre of symmetry of the curve y = (1/(x + 2))

$find the centre of symmetry of the curve$ $y = \frac{1}{x + 2}$

Question Number 85222 Answers: 0 Comments: 3

In C++ What is the sections doing ? and What is the output from the sections below ? a. int p=o; for (int i=1; i<=30; i++){ if (i%5==0) p+=i; } cout<<p<<endl; b. int count=2; int g=0; while (count<=50){ g=count; cout<<g<<endl; count +=2; } cout<<count<<endl;

$In C + +$ $What is the sections doing ? and$ $What is the output from the sections$ $below ?$ $a . int p = o;$ $for (int i = 1; i <= 30; i + +) {$ $if (i % 5 == 0)$ $p + = i;$ $}$ $cout << p << endl;$ $b . int count = 2;$ $int g = 0;$ $while (count <= 50) {$ $g = count;$ $cout << g << endl;$ $count + = 2;$ $}$ $cout << count << endl;$