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Question Number 67745 Answers: 3 Comments: 0

solve the system of equations { ((3∣x−5∣+4=y)),((∣y−3∣=4x−12)) :}

$s o l v e t h e s y s t e m o f e q u a t i o n s {\begin{cases} 3 ∣ x - 5 ∣ + 4 = y \\ ∣ y - 3 ∣= 4 x - 12 \end{cases}$

Question Number 67697 Answers: 1 Comments: 0

⋓si⋒g ChineseRemainderTheorm ∂etermine polynomial p(x) such that p(x)≡8(mod x+1) p(x)≡−24(mod x+3) p(x)≡6(mod x) p(x)≡0(mod x+2)

$⋓ si ⋒ g ChineseRemainderTheorm$ $\partial etermine polynomial p (x) such that$ $p (x) \equiv 8 (\mod x + 1)$ $p (x) \equiv - 24 (\mod x + 3)$ $p (x) \equiv 6 (\mod x)$ $p (x) \equiv 0 (\mod x + 2)$

Question Number 67688 Answers: 0 Comments: 1

A relation R defined by _((x,y)) R_((u,v)) ⇔ v^2 −y^2 = u^2 −x^2 show that R is an equivalent Relation.

$A r e l a t i o n R d e f i n e d b y_{(x, y)} R_{(u, v)} \Leftrightarrow v^{2} - y^{2} = u^{2} - x^{2}$ $s h o w t h a t R i s a n e q u i v a l e n t R e l a t i o n .$

Question Number 67687 Answers: 0 Comments: 3

find the range of values of ∣((x^2 −9)/3_ )∣= ((9−x^2 )/3)

$f i n d t h e r a n g e o f v a l u e s o f$ $∣ \frac{x^{2} - 9}{3_{}} ∣= \frac{9 - x^{2}}{3}$

Question Number 67686 Answers: 0 Comments: 2

given that the roots of the equation 4x^2 + 6x + 9 =0 are λ and δ where λ = (1 + α^2 +β^2 ) and δ = α^3 + β^3 find an equation whose roots are (1/(αλ)) and (1/(βδ))

$g i v e n t h a t t h e r o o t s o f t h e e q u a t i o n 4 x^{2} + 6 x + 9 = 0 a r e λ a n d δ w h e r e$ $λ = (1 + α^{2} + β^{2}) a n d δ = α^{3} + β^{3}$ $f i n d a n e q u a t i o n w h o s e r o o t s a r e$ $\frac{1}{α λ} a n d \frac{1}{β δ}$

Question Number 67684 Answers: 0 Comments: 2

given the function f(x) = { ((x^2 , for 0≤ x< 2)),((ax + 3, for 2≤ x < 4)) :} is periodic of period 4, and is continuous. a) Find the value of a. b) Find the valu of f(6) c) sketch the graph for y =f(x). help me please, for the graph i don′t know wbere to put y=x^2 and y = ax + 3 and where do i put a closed dot and an open dot.

$g i v e n t h e f u n c t i o n$ $f (x) = {\begin{cases} x^{2}, f o r 0 ⩽ x < 2 \\ a x + 3, f o r 2 ⩽ x < 4 \end{cases}$ $i s p e r i o d i c o f p e r i o d 4, a n d i s c o n t i n u o u s .$ $a) F i n d t h e v a l u e o f a .$ $b) F i n d t h e v a l u o f f (6)$ $c) s k e t c h t h e g r a p h f o r y = f (x) .$ $h e l p m e p l e a s e, f o r t h e g r a p h i {d o n}^{'} t k n o w w b e r e t o p u t y = x^{2} a n d y = a x + 3 a n d$ $w h e r e d o i p u t a c l o s e d d o t a n d a n o p e n d o t .$

Question Number 67664 Answers: 0 Comments: 2

show that ∃ n ∈ N^(+ ) : sin^n x + cos^n x = 1 and cosh^n x − sinh^n x = 1. Hint: use Induction method.

$s h o w t h a t \exists n \in N^{+} : {s i n}^{n} x + {c o s}^{n} x = 1 a n d {c o s h}^{n} x - {s i n h}^{n} x = 1 .$ $H i n t : u s e I n d u c t i o n m e t h o d .$

Question Number 67662 Answers: 0 Comments: 2

please explain the fact that ∫(1/x)dx = ln x + k

$p l e a s e e x p l a i n t h e f a c t t h a t$ $\int \frac{1}{x} d x = l n x + k$

Question Number 67659 Answers: 0 Comments: 3

Help me obtain the value of e from (1 + (1/n))^n how do i go about it.

$H e l p m e o b t a i n t h e v a l u e o f e f r o m$ ${(1 + \frac{1}{n})}^{n} h o w d o i g o a b o u t i t .$

Question Number 67631 Answers: 0 Comments: 3

Can you please tell me, where does this formula come from? And what means the factorial of a non- integer number? π = ((1/2)!)^2 × 4 I′ve verified the above equation with calculator. Thank you

$Can you please tell me, where does this$ $formula come from ?$ $And what means the factorial of a non -$ $integer number ?$ $π = {(\frac{1}{2}!)}^{2} \times 4$ $I^{'} v e v e r i f i e d t h e a b o v e e q u a t i o n w i t h c a l c u l a t o r .$ $Thank you$

Question Number 67482 Answers: 0 Comments: 1

I have tried to solve Q#67299 Please see and give critical remarks

$You can't use 'macro parameter character #' in math mode$ $P l e a s e s e e a n d g i v e c r i t i c a l r e m a r k s$

Question Number 67471 Answers: 0 Comments: 4

Evaluate:∫(√(x(√(x+1)))) dx

$E v a l u a t e : \int \sqrt{x \sqrt{x + 1}} d x$

Question Number 68728 Answers: 0 Comments: 0

dear scientist. i did some research on the energy obtained from the sun any other source by a liquid, of density ρ , velocity v, viscosity η and distance travelled d. i came out with the equation E = k ( vρ η^3 d^2 ) where k is a costant i still need to determine from more experiment. But please i want you guys great people to check if the equation is in confirmity and if atall it is correct so i can do some changes. thanks in advanced dear scientist.

$d e a r s c i e n t i s t .$ $i d i d s o m e r e s e a r c h o n t h e e n e r g y o b t a i n e d f r o m t h e s u n$ $a n y o t h e r s o u r c e b y a l i q u i d, o f d e n s i t y ρ, v e l o c i t y v, v i s c o s i t y η a n d d i s t a n c e$ $t r a v e l l e d d .$ $i c a m e o u t w i t h t h e e q u a t i o n$ $E = k (v ρ η^{3} d^{2})$ $w h e r e k i s a c o s t a n t i s t i l l n e e d t o d e t e r m i n e f r o m m o r e$ $e x p e r i m e n t . B u t p l e a s e i w a n t y o u g u y s g r e a t p e o p l e t o$ $c h e c k i f t h e e q u a t i o n i s i n c o n f i r m i t y a n d i f a t a l l i t i s c o r r e c t$ $s o i c a n d o s o m e c h a n g e s .$ $t h a n k s i n a d v a n c e d d e a r s c i e n t i s t .$

Question Number 67299 Answers: 2 Comments: 5

G(x)= (x+1)(x+3)Q(x) + px +q a) Given that G(x) leaves a remainder of 8 and −24 when divided by (x+1) and (x+3) respectively,find the remainder when G(x) is divided by (x+1)(x+3). b) Given that x+2 is a factor of G(x) and that the graph of G(x) passes through the point with coordinates (0,6) find G(x)

$G (x) = (x + 1) (x + 3) Q (x) + p x + q$ $a) G i v e n t h a t G (x) l e a v e s a r e m a i n d e r o f 8 a n d - 24 w h e n d i v i d e d b y (x + 1) a n d$ $(x + 3) r e s p e c t i v e l y, f i n d t h e r e m a i n d e r w h e n G (x) i s d i v i d e d b y (x + 1) (x + 3) .$ $b) G i v e n t h a t x + 2 i s a f a c t o r o f G (x) a n d t h a t t h e g r a p h o f G (x) p a s s e s t h r o u g h$ $t h e p o i n t w i t h c o o r d i n a t e s (0, 6) f i n d G (x)$

Question Number 67298 Answers: 0 Comments: 2

Find the third degree polynomial which vanishes when x =−1 and x = 2, which has a value 8 when x =0 and leaves a remainder ((16)/3) when divided by 3x + 2.

$F i n d t h e t h i r d d e g r e e p o l y n o m i a l w h i c h v a n i s h e s w h e n$ $x = - 1 a n d x = 2, w h i c h h a s a v a l u e 8 w h e n x = 0 a n d l e a v e s a r e m a i n d e r \frac{16}{3} w h e n$ $d i v i d e d b y 3 x + 2 .$

Question Number 67148 Answers: 0 Comments: 6

explicitez la suite u_n definie par la relation; { ((u_0 =0, u_1 =1)),((u_(n+2) =u_(n+1) +u_n ∀n∈∤N)) :} u_n =???????? −calculer la lim _(n→∞) (u_(n+1) /u_n )=??? −montre que Σ_(k=0) ^n u_k =u_(n+2) −1 voila^′

$explicitez la suite u_{n} definie par la relation;$ ${\begin{cases} u_{0} = 0, u_{1} = 1 \\ u_{n + 2} = u_{n + 1} + u_{n} \forall n \in∤ N \end{cases}$ $u_{n} = ? ? ? ? ? ? ? ?$ $- calculer la \lim \underset{n \to \infty}{} \frac{u_{n + 1}}{u_{n}} = ? ? ?$ $- montre que \underset{k = 0}{\sum^{n}} u_{k} = u_{n + 2} - 1$ ${voila}^{^{'}}$

Question Number 67004 Answers: 1 Comments: 0

Question Number 66988 Answers: 0 Comments: 0

Question Number 66986 Answers: 0 Comments: 1

Question Number 66985 Answers: 1 Comments: 0

The external length,width and height of an open rectangular container are 41cm,21cm and 15.5cm respectively. The thickness of the material making the container is 5mm.If the container has 8litres of water,calculate the internal height above the water level. Ans:5cm

$The external length, width and height$ $of an open rectangular container are$ $41 cm, 21 cm and 15 . 5 cm respectively .$ $The thickness of the material making$ $the container is 5 mm . If the container$ $has 8 litres of water, calculate the$ $internal height above the water level .$ $A n s : 5 c m$

Question Number 66932 Answers: 1 Comments: 0

which of the sequences converges ? 1) a_n = n−(1/n) 2) a_n = ((−1)^n +1)(((n+1)/n))

$w h i c h o f t h e s e q u e n c e s c o n v e r g e s ?$ $1) a_{n} = n - \frac{1}{n}$ $2) a_{n} = ({(- 1)}^{n} + 1) (\frac{n + 1}{n})$

Question Number 66865 Answers: 1 Comments: 1

A and B are two towns 360km apart. An express bus departs from A at 8a.m and maintains an average speed of 90km/h between A and B. Another bus starts from B also at 8a.m and moves towards A making four stops at four equally spaced points between B and A. Each stop is of duration 5 minutes and the average speed between any two stops is 60km/h. Calculate the distance between the two buses at 10p.m.

$A a n d B a r e t w o t o w n s 360 k m a p a r t .$ $A n e x p r e s s b u s d e p a r t s f r o m A a t$ $8 a . m a n d m a i n t a i n s a n a v e r a g e$ $s p e e d o f 90 k m / h b e t w e e n A a n d B .$ $A n o t h e r b u s s t a r t s f r o m B a l s o a t$ $8 a . m a n d m o v e s t o w a r d s A m a k i n g$ $f o u r s t o p s a t f o u r e q u a l l y s p a c e d$ $p o i n t s b e t w e e n B a n d A . E a c h s t o p$ $i s o f d u r a t i o n 5 m i n u t e s a n d t h e$ $a v e r a g e s p e e d b e t w e e n a n y t w o s t o p s$ $i s 60 k m / h . C a l c u l a t e t h e d i s t a n c e$ $b e t w e e n t h e t w o b u s e s a t 10 p . m .$

Question Number 66868 Answers: 0 Comments: 3

A town N is 340km due west of town G and town K is due west of town N. A helicopter Zebra left G for K at 9a.m. Another helicopter Buffalo left N for K at 11a.m. Helicopter Buffalo travelled at an average speed of 20km/h faster than helicopter Zebra. If both helicopters reached K at 12.30p.m, find the speed of helicopter Buffalo.

$A t o w n N i s 340 k m d u e w e s t o f$ $t o w n G a n d t o w n K i s d u e w e s t$ $o f t o w n N . A h e l i c o p t e r Z e b r a$ $l e f t G f o r K a t 9 a . m . A n o t h e r$ $h e l i c o p t e r B u f f a l o l e f t N f o r K$ $a t 11 a . m . H e l i c o p t e r B u f f a l o$ $t r a v e l l e d a t a n a v e r a g e s p e e d o f$ $20 k m / h f a s t e r t h a n h e l i c o p t e r$ $Z e b r a . I f b o t h h e l i c o p t e r s r e a c h e d$ $K a t 12.30 p . m, f i n d t h e s p e e d o f$ $h e l i c o p t e r B u f f a l o .$

Question Number 66856 Answers: 1 Comments: 0

Two towns T and S are 300 km apart. Two buses A and B started from T at the same time travelling towards S. Bus B, travelling at an average speed of 10km/h greater than that of A reached S 1(1/4) hours earlier. (a) Find the average speed of A (b) How far was A from T when B reached S.

$T w o t o w n s T a n d S a r e 300 k m a p a r t .$ $T w o b u s e s A a n d B s t a r t e d f r o m$ $T a t t h e s a m e t i m e t r a v e l l i n g t o w a r d s$ $S . B u s B, t r a v e l l i n g a t a n a v e r a g e$ $s p e e d o f 10 k m / h g r e a t e r t h a n t h a t$ $o f A r e a c h e d S 1 \frac{1}{4} h o u r s e a r l i e r .$ $(a) F i n d t h e a v e r a g e s p e e d o f A$ $(b) H o w f a r w a s A f r o m T w h e n$ $B r e a c h e d S .$

Question Number 66852 Answers: 0 Comments: 3

Question Number 66851 Answers: 2 Comments: 1

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