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Question Number 60247 Answers: 0 Comments: 0

A uniform pole PQ, 30 m long and of mass 4 kg is carried by a boy at P and a man 8 m away from Q. Find the distance from P where a mass of 20 kg should be attached so that the man′s support is twice that of the boy, if the system is in equilibrium [Take g=10ms^(−2) ]

$A uniform pole PQ, 30 m long and of mass$ $4 kg is carried by a boy at P and a man$ $8 m away from Q . Find the distance from$ $P where a mass of 20 kg should be attached$ $so that the {man}^{'} s support is twice that$ $of the boy, if the system is in equilibrium$ $[Take g = {10 ms}^{- 2}]$

Question Number 60227 Answers: 0 Comments: 0

Question Number 60219 Answers: 1 Comments: 1

C=((2𝛑𝛜𝛜_0 L)/(ln((R_2 /R_1 )))). prove.

$C = \frac{2 π ε ε_{0} L}{\ln (\frac{R_{2}}{R_{1}})} .$ $prove .$

Question Number 60202 Answers: 0 Comments: 0

construct the point M^′ =(1/2)((((z+∣z∣))/2))

$c o n s t r u c t t h e p o i n t M^{^{'}} = \frac{1}{2} (\frac{(z + ∣ z ∣)}{2})$

Question Number 60143 Answers: 1 Comments: 0

Two passenger trains, A and B, 450km apart, start to move towards each other at the same time and meet after 2 hours. If train B, travels (8/7) as fast as train A, find the speed of each train.

$Two passenger trains, A and B, 450 km apart,$ $start to move towards each other at the$ $same time and meet after 2 hours . If train B,$ $travels \frac{8}{7} as fast as train A, find the speed$ $of each train .$

Question Number 60135 Answers: 1 Comments: 0

Question Number 60022 Answers: 0 Comments: 0

construct M^′ z^′ =(1/2)(((z+∣z∣)/3))

$c o n s t r u c t M^{^{'}} z^{^{'}} = \frac{1}{2} (\frac{z + ∣ z ∣}{3})$

Question Number 60021 Answers: 1 Comments: 0

Question Number 60001 Answers: 0 Comments: 0

Question Number 59935 Answers: 0 Comments: 1

sir malwan you must revise analytical function and complex analysis...

$s i r m a l w a n y o u m u s t r e v i s e a n a l y t i c a l f u n c t i o n a n d c o m p l e x a n a l y s i s . . .$

Question Number 59787 Answers: 2 Comments: 0

Question Number 59780 Answers: 1 Comments: 0

An earth-based observer sees rocket A moving at 0.70c directly towards rocket B,which is moving towards A at 0.80c. How fast does rocket A sees rocket B approaching?

$A n e a r t h - b a s e d o b s e r v e r s e e s r o c k e t A$ $m o v i n g a t 0.70 c d i r e c t l y t o w a r d s r o c k e t$ $B, w h i c h i s m o v i n g t o w a r d s A a t 0.80 c .$ $H o w f a s t d o e s r o c k e t A s e e s r o c k e t B$ $a p p r o a c h i n g ?$

Question Number 59752 Answers: 1 Comments: 2

Question Number 59685 Answers: 0 Comments: 0

Question Number 59675 Answers: 0 Comments: 0

you are welcome sir ali.

$y o u a r e w e l c o m e s i r a l i .$

Question Number 59655 Answers: 1 Comments: 3

Question Number 59639 Answers: 0 Comments: 3

Question Number 59588 Answers: 1 Comments: 1

find x,y in R (x+yi)^3 =((1+(√(15)) i)/((√5) − (√3) i))

$f i n d x, y i n R$ ${(x + y i)}^{3} = \frac{1 + \sqrt{15} i}{\sqrt{5} - \sqrt{3} i}$

Question Number 59505 Answers: 2 Comments: 0

Two particles P and Q move towards each other along a straight line MN, 51 meters long. P starts fromM with velocity 5 ms^(−1) and constant acceleration of 1 ms^(−2) . Q starts from N at the same time with velocity 6 ms^(−1) and at a constant acceleration of 3 ms^(−2) . Find the time when the: (a) particles are 30 metres apart; (b) particles meet; (c) velocity of P is (3/4) os the velocity of Q.

$Two particles P and Q move towards each$ $other along a straight line M N, 51 meters$ $long . P starts from M with velocity 5 {ms}^{- 1}$ $and constant acceleration of 1 {ms}^{- 2} . Q starts$ $from N at the same time with velocity 6 {ms}^{- 1}$ $and at a constant acceleration of 3 {ms}^{- 2} .$ $Find the time when the :$ $(a) particles are 30 metres apart;$ $(b) particles meet;$ $(c) velocity of P is \frac{3}{4} os the velocity of Q .$