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Question Number 214293 by muallimRiyoziyot last updated on 04/Dec/24
P(x)⋮(x2+3)mod(5x−1)P(x)⋮(x−2)mod(16)P(x)⋮(x2+3)(x−2)mod(?)
Answered by MrGaster last updated on 24/Dec/24
(P(x)⋮(x2+3)(x−2)mod((5x−1)⋅16))
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