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Question Number 118634 by ajfour last updated on 18/Oct/20

$P r o v e t h a t t h e e q u a t i o n o f t h e c i r c l e$ $p a s s i n g t h r o u g h t h e p o i n t s o f$ $i n t e r s e c t i o n o f t h e s e t w o c u r v e s :$ $y = 1 + \frac{c}{x}; y = x^{2} (c < \frac{2}{3 \sqrt{3}})$ $i s {(x - \frac{c}{2})}^{2} + {(y - 1)}^{2} = 1 + \frac{c^{2}}{4} .$
Commented by necxxx last updated on 18/Oct/20

$s i r A j f o u r, y o u a n d I k n o w t h e s e y o u r$ $q u d s t i o n s a r e f o r M r W a n d B . e . h . i . . . l o l$ $I r e a l l y a p p r e c i a t e y o u r q u e s t i o n s; t h e y$ $r e m i n d m e t h a t {t h e r e}^{'} s m o r e t o w h a t w e$ $e v e r k n o w .$
Commented by ajfour last updated on 18/Oct/20

$t h a n k s S i r, t h i s q u e s t i o n$ $i^{'} v e c r e a t e d m y s e l f i s r e a l l y n i c e .$ $A n y o n e i n c l u d i n g y o u c a n a t t e m p t i t ★$
Commented by ajfour last updated on 18/Oct/20

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