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Question Number 101616 by 175 last updated on 03/Jul/20

Commented by Tinku Tara last updated on 03/Jul/20

$Please post question where you$ $yourself doubt .$
	Answered by mr W last updated on 03/Jul/20

	$90 \times \frac{35 \times \frac{3}{4}}{90 - 35} = 42.95 k m$
	Commented by 175 last updated on 03/Jul/20
	how? Explain
	Commented by mr W last updated on 03/Jul/20

	$a s t h e c a r s t a r t e d, t h e m o t o r c y c l e$ $h a d t r a v e l e d a d i s t a n c e 35 \times \frac{3}{4} .$ $i n o n e h o u r t h e c a r c a n t r a v e l 90 - 35$ $= 55 k m m o r e t h a n t h e m o t o r c y c l e .$ $s u c h t h a t t h e y m e t, t h e c a r n e e d e d$ $\frac{35 \times \frac{3}{4}}{90 - 35} h o u r s . t h e d i s t a n c e t h e c a r$ $t r a v e l e d i s 90 \times \frac{35 \times \frac{3}{4}}{90 - 35}, w h i c h i s a l s o$ $t h e t o t a l d i s t a n c e t h e m o t o r c y c l e$ $t r a v e l e d .$
	Commented by mr W last updated on 03/Jul/20

	$e x c u s e m e b o y o r s i r!$ $a s i s a w t h i s q u e s t i o n o f y o u, i t h o u g h t$ $y o u a r e s t i l l i n e l e m e n t a r y s c h o o l .$ $a s y o u s a i d y o u {d o n}^{'} t u n d e r s t a n d m y$ $a n s w e r, i t r i e d t o e x p l a i n i n a w a y t h a t$ $a c h i l d o f t h i r d c l a s s m a y u n d e r s t a n d .$ $b u t a s i s a w t h e o t h e r p o s t s o f y o u,$ $O M G, y o u m u s t b e a l e a s t a c o l l e g e$ $s t u d e n t . m a n y q u e s t i o n s f r o m y o u$ $a r e e v e n t o o h i g h f o r m e, s u c h a s$ $f o l l o w i n g o n e . h o w c a n s o m e b o d y$ $u n d e r s t a n d i n t e g r a l c a l c u l u s, b u t$ ${d o e s n}^{'} t u n d e r s t a n d b a s i c a r i t h m e t i c ?$
	Commented by mr W last updated on 03/Jul/20

	Commented by mr W last updated on 03/Jul/20

	$t o b e h o n e s t, i w a s d i s p l e a s e d a s i$ $r e a l i s e d t h i s .$
	Commented by Tinku Tara last updated on 03/Jul/20

	$Also same as in q 101329 .$
	Answered by Dwaipayan Shikari last updated on 03/Jul/20

	$R e l a t i v e v e l o c i t y = (90 - 35) \frac{k m}{h}$ $T h e s c o o t e r h a s c r o s s e d (35 \times \frac{3}{4}) k m d u r i n g t h i s t i m e .$ $T i m e t a k e n b y c a r t o r e a c h t h e m o t o r c y c l i s t = \frac{35 \times \frac{3}{4}}{90 - 35} h$ $D i s t a n c e c o v e r e d = 90 \times \frac{35 \times \frac{3}{4}}{90 - 35} = 42.95 ★ k m$
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