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Question Number 10166 by Joel575 last updated on 28/Jan/17

Commented by Joel575 last updated on 28/Jan/17

$$\mathrm{Two}\mathrm{circles}\mathrm{with}\mathrm{same}\mathrm{center}\mathrm{point}\mathrm{have}$$$${\mathrm{R}}_1\mathrm{and}{\mathrm{R}}_2\mathrm{with}{\mathrm{R}}_1<{\mathrm{R}}_2$$$$\mathrm{If}\mathrm{the}\mathrm{long}\mathrm{of}\mathrm{AB}\mathrm{bowstring}\mathrm{is}10\mathrm{cm},$$$$\mathrm{count}\mathrm{the}\mathrm{area}\mathrm{of}\mathrm{blue}\mathrm{shade}$$

Answered by mrW1 last updated on 28/Jan/17

$$A_{blue}=\pi (R_2^2-R_1^2)=\pi \times {\left(\frac{L}{2}\right)}^2=\pi {\left(\frac{10}{2}\right)}^2=25\pi$$

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