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Question Number 101767 by 175mohamed last updated on 04/Jul/20

Commented by mr W last updated on 04/Jul/20

$$aCDcancoverawallareaof$$$$2\times \frac{D}{2}\times \frac{\sqrt{3}}{2}\times D=\frac{\sqrt{3}{D}^2}{2}$$$$numberofCDsneededtocover$$$$6m\times 4mwallarea:$$$$\frac{6\times 4m^2}{\frac{\sqrt{3}\times 0.{12}^2}{2}{m}^2}\approx 1425$$

Commented by mr W last updated on 04/Jul/20

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