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Question Number 104624 by dw last updated on 22/Jul/20

Commented by dw last updated on 22/Jul/20

$$?$$

Commented by Dwaipayan Shikari last updated on 22/Jul/20

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Commented by Dwaipayan Shikari last updated on 22/Jul/20

$$2019!{log}_{1001}501=0.8998.2019!=(a-\frac{27}{100})2019!\left(approximately\right)$$$${log}_{72}144=1.16=a$$$$$$

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