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Question Number 105743 by Skabetix last updated on 31/Jul/20
Commented by Skabetix last updated on 31/Jul/20
thankyouinadvance
Answered by john santu last updated on 31/Jul/20
∫badf(x)dx1+f2(x)dx+f3(b)−f3(a)∫badf(x)1+f2(x)+f3(b)−f3(a)[ln∣f(x)+1+f2(x)∣]ab+f3(b)−f3(a)ln∣f(b)+1+f2(b)f(a)+1+f2(a)∣+f3(b)−f3(a)
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