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Question Number 10774 by j.masanja06@gmail.com last updated on 24/Feb/17

Answered by sandy_suhendra last updated on 24/Feb/17

= determinant (((log_3 1024    1)),((log_3 8            2)))× determinant (((log_2 3    log_4 3)),((log_3 4    log_3 4)))  =(2log_3 1024−log_3 8)×(log_2 3.log_3 4−log_4 3.log_3 4)      =(log_3 ((1024^2 )/8))×(log_2 4−1)  =(log_3 2^(17) )×(2−1) = 17 log_3 2

=|log310241log382|×|log23log43log34log34|=(2log31024log38)×(log23.log34log43.log34)=(log3102428)×(log241)=(log3217)×(21)=17log32

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