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Question Number 10820 by chux last updated on 26/Feb/17

Answered by bar Jesús last updated on 26/Feb/17

$$8{log}_{2}x={log}_2{x}^8,x=2$$$$(x-1){log}_{x}2={log}_x{2}^{(x-1)},x=2$$$$3^x=3^2=9,x=2$$$$$$$$8{log}_{2}2+(2-1){log}_{2}2=3^2$$$$8+1=9$$$$9=9$$$$$$$$$$

Commented by mrW1 last updated on 27/Feb/17

$$andx\approx 1.3855$$

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