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Question Number 111497 by bemath last updated on 04/Sep/20
Commented by kaivan.ahmadi last updated on 04/Sep/20
lett=x13+6x12−30x1+x12x2−5x12x2+6x+7=0x12+6x1=−7andx3+6x2+7x=0⇒x13+6x12=−7x1⇒x13+6x12−30x1=−7x1−30x1=−37x1⇒t=−37x1+x12x2−5x12=x1(−37+x1x2)−5x12=x1(−37+7)−5x12=−30x1−5x12=−5(x12+6x1)=−5×(−7)=35
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