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Question Number 114295 by mathdave last updated on 18/Sep/20
Answered by mr W last updated on 19/Sep/20
saythenumberis[abcde]letA=a+c+eB=b+dA+B=41(asgiven)A−B=0or±11,±22,...⇒A=20,B=21(impossible,sinceB<2×9=18)⇒A=26,B=15⇒A=37,B=4(impossible,sinceA<3×9=27)sowehaveonlyonepossibility:A=26,B=15⇒A=9+9+8⇒B=9+6⇒smallestnumberis86999⇒largestnumberis99968
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