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Question Number 11540 by tawa last updated on 28/Mar/17

Answered by sandy_suhendra last updated on 28/Mar/17

$$\left(1\right)$$$$\mathrm{S}=3\mathrm{cm}=0.03\mathrm{m}$$$$\mathrm{m}=7\mathrm{g}=7.{10}^{-3}\mathrm{kg}$$$${\mathrm{V}}_{\mathrm{o}}=450\mathrm{m}/\mathrm{s}$$$${\mathrm{V}}_{\mathrm{t}}=175\mathrm{m}/\mathrm{s}$$$$$$$$\mathrm{W}=\mathrm{\Delta }\mathrm{KE}$$$$\mathrm{\Sigma }\mathrm{F}.\mathrm{S}=\frac{1}{2}\mathrm{m}({\mathrm{V}}_{\mathrm{t}}^2-{\mathrm{V}}_{\mathrm{o}}^2)$$$$-\mathrm{F}\times 0.03=\frac{1}{2}\times 7.{10}^{-3}\times ({175}^2-{450}^2)$$$$-0.03\mathrm{F}=-601.5625$$$$\mathrm{F}=20,052.083\mathrm{N}$$

Commented by tawa last updated on 28/Mar/17

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

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