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Question Number 116759 by bemath last updated on 06/Oct/20

Answered by bobhans last updated on 06/Oct/20

$$=\underset{\mathrm{n}=0}{\prod ^{21}}({2030}^2-{(2040-\mathrm{n})}^2)$$$$=\underset{\mathrm{n}=0}{\prod ^{21}}(2030+(2040-\mathrm{n})(2030-(2040-\mathrm{n}))$$$$=\underset{\mathrm{n}=0}{\prod ^{21}}(4070-\mathrm{n})(\mathrm{n}-10)$$$$=(-40700)\times (-36621)\times ...\times 0\times ...(-32544)\times ...\times \left(44539\right)$$$$=0$$

Answered by Dwaipayan Shikari last updated on 06/Oct/20

$$0$$$$({2030}^2-{2040}^2).......({2030}^2-{2030}^2)....$$$$Otherterm\times ....0=0$$

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