Math Question and Answers


Question and Answers Forum

All Questions Topic List
Algebra Questions
Previous in All Question Next in All Question
Previous in Algebra Next in Algebra
Question Number 11813 by b.e.h.i.8.3.4.1.7@gmail.com last updated on 01/Apr/17

Commented by mrW1 last updated on 01/Apr/17

$d e p e n d i n g o n t h e v a l u e s o f a a n d b,$ $t h e r e a r e 5 c a s e s :$ $1) n o s o l u t i o n$ $2) o n e s o l u t i o n$ $3) t w o s o l u t i o n s$ $4) t h r e e s o l u t i o n s$ $5) f o u r s o l u t i o n s$
Commented by mrW1 last updated on 01/Apr/17

Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on 01/Apr/17

$t h a n k y o u v e r y m u c h f o r y o u r a n s w e r .$ $a a n d b, a r e \in N$
	Answered by sma3l2996 last updated on 01/Apr/17

	$x = a - y^{2}$ ${(a - y^{2})}^{2} + y^{2} = b$ $a^{2} + y^{4} - 2 {a y}^{2} + y^{2} = b$ $y^{4} - (2 a - 1) y^{2} = b - a^{2}$ $y^{4} - \frac{(2 a - 1) \times 2}{2} y^{2} + {(\frac{2 a - 1}{2})}^{2} = b - a^{2} + {(\frac{2 a - 1}{2})}^{2}$ ${(y^{2} - \frac{2 a - 1}{2})}^{2} = b - a^{2} + a^{2} - a + \frac{1}{4} = \frac{4 (b - a) + 1}{4}$ $y^{2} = \underline{+} \frac{\sqrt{4 (b - a) + 1}}{2} + \frac{2 a - 1}{2}$ $y = \underline{+} \sqrt{\frac{\underline{+} \sqrt{4 (b - a) + 1} + 2 a - 1}{2}}$ $x = a - y^{2} = \underline{+} \frac{\sqrt{4 (b - a) + 1} + 2 a - 1}{2} + a$
	Commented by mrW1 last updated on 01/Apr/17

	$l i n e 2 s h o u l d b e :$ ${(a - y^{2})}^{2} + y = b$
	Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on 01/Apr/17

	$t h a n k y o u f o r a n s w e r . b u t a s m r W 1,$ $p i o n t e d : t h e r i s a l i t t l e m i s t a k e i n$ $You can't use 'macro parameter character #' in math mode$
	Commented by sma3l2996 last updated on 01/Apr/17

	$y e s y o u a l r i g h t$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum