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Question Number 12074 by sin (x) last updated on 11/Apr/17

Answered by ajfour last updated on 11/Apr/17

Commented by ajfour last updated on 11/Apr/17

$$Misthemid-pointofCD.$$$$letsideoftrianglebe\mathit{a}.$$$$\mathbf{BM}=\mathbf{BC}-\mathbf{CM}$$$$=\mathbf{a}-\frac{\mathbf{a}+8}{2}=\frac{\mathbf{a}-8}{2}$$$$\mathbf{BE}=\mathbf{BM}/\cos 60=\mathbf{a}-8$$$$\mathbf{AB}=\mathbf{a}$$$$\mathbf{AE}=\mathbf{AB}-\mathbf{BE}=\mathbf{a}-(\mathbf{a}-8)=8\mathrm{cm}.$$

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