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Question Number 12082 by chux last updated on 12/Apr/17

Answered by ajfour last updated on 12/Apr/17

$$\mathrm{t}=\frac{\mathrm{s}}{\mathrm{v}}=\frac{\mathrm{s}}{\left(\mathrm{c}/\mu \right)}=\frac{\mu \mathrm{s}}{\mathrm{c}}$$$$=\frac{(1.5)(0.9\times {10}^{-2}\mathrm{m})}{\left(3\times {10}^8\mathrm{m}/\mathrm{s}\right)}$$$$=45\times {10}^{-12}\mathrm{s}$$

Commented by chux last updated on 12/Apr/17

$$\mathrm{wow}!\mathrm{thanks}$$

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