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Question Number 122075 by peter frank last updated on 13/Nov/20

Answered by MJS_new last updated on 14/Nov/20

$$\mathrm{seriously}???$$$$=\underset{0}{\stackrel{1}{\int }}\mid x+1\mid dx=\underset{0}{\stackrel{1}{\int }}(x+1)dx={[\frac{x^2}{2}+x]}_0^1=\frac{3}{2}$$

Commented by peter frank last updated on 14/Nov/20

$$\mathrm{thank}\mathrm{you}$$

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