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Question Number 122160 by benjo_mathlover last updated on 14/Nov/20

Answered by liberty last updated on 14/Nov/20

$$\underset{1}{\stackrel{2}{\int }}[\mathrm{f}\left(\mathrm{x}\right)+1]\mathrm{dx}-\underset{1}{\stackrel{2}{\int }}[\mathrm{f}\left(\mathrm{t}\right)+-1]\mathrm{dt}=$$$${\int }_0^2\mathrm{f}\left(\mathrm{x}\right)\mathrm{dx}-{\int }_0^2\mathrm{f}\left(\mathrm{t}\right)\mathrm{dt}+\underset{1}{\stackrel{2}{\int }}\mathrm{dx}+{\int }_0^2\mathrm{dt}$$$$=0+{\left[\mathrm{x}\right]}_1^2+{\left[\mathrm{t}\right]}_1^2=2.$$$$$$

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