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Question Number 12257 by b.e.h.i.8.3.4.1.7@gmail.com last updated on 16/Apr/17

Answered by sma3l2996 last updated on 17/Apr/17

(a+b−2ab)^2 +(a+b−1)^2 =(a^2 +b^2 +4a^2 b^2 −4ab^2 +2a(b−2ab))+(a^2 +b^2 +1−2b+2a(b−1))  =2a^2 +2b^2 +4a^2 b^2 −4ab^2 +2ab−4a^2 b−2b+2ab−2a+1  =2a^2 (1+2b^2 −2b)+2a(2b−2b^2 −1)+2b^2 −2b+1  =(2b^2 −2b+1)(2a^2 −2a+1)  so it′s correct

(a+b2ab)2+(a+b1)2=(a2+b2+4a2b24ab2+2a(b2ab))+(a2+b2+12b+2a(b1))=2a2+2b2+4a2b24ab2+2ab4a2b2b+2ab2a+1=2a2(1+2b22b)+2a(2b2b21)+2b22b+1=(2b22b+1)(2a22a+1)soitscorrect

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