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Question Number 137209 by JulioCesar last updated on 31/Mar/21

Answered by bemath last updated on 31/Mar/21

$$\int {(\sec {}^2\mathrm{x}-1)}^2\sec \mathrm{x}\mathrm{dx}$$$$=\int (\sec {}^5\mathrm{x}-2\sec {}^3\mathrm{x}+\sec \mathrm{x})\mathrm{dx}$$$$\mathrm{now}\mathrm{it}\mathrm{easy}\mathrm{to}\mathrm{solve}$$

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