All Questions Topic List
Integration Questions
Previous in All Question Next in All Question
Previous in Integration Next in Integration
Question Number 138206 by Bekzod Jumayev last updated on 11/Apr/21
Commented by Bekzod Jumayev last updated on 11/Apr/21
Help?
Answered by mr W last updated on 11/Apr/21
=∫x12x12×3x12×3×4x12×3×4×5...dx=∫x12+12×3+12×3×4+12×3×4×5+...dx=∫x(1+1+12!+13!+14!+15!+...)−2dx=∫xe−2dx=xe−1e−1+C
Terms of Service
Privacy Policy
Contact: info@tinkutara.com