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Question Number 138224 by Bekzod Jumayev last updated on 11/Apr/21

Commented by Bekzod Jumayev last updated on 11/Apr/21

$$Help$$

Answered by MJS_new last updated on 11/Apr/21

$$\frac{d}{dx}\left[p\left(x\right)\right]=5\Rightarrow p\left(x\right)=5x+C_1$$$$\frac{d}{dx}\left[q\left(x\right)\right]=4\Rightarrow q\left(x\right)=4x+C_2$$$$\mathrm{we}\mathrm{can}\mathrm{only}\mathrm{solve}\mathrm{if}\mathrm{we}\mathrm{know}{C}_1,C_2$$$$\mathrm{if}{C}_1=C_2=0$$$$\frac{d}{dx}\left[\frac{p\left(x\right)q\left(x\right)}{p\left(x\right)+q\left(x\right)}\right]=\frac{d}{dx}\left[\frac{20x^2}{9x}\right]=\frac{d}{dx}\left[\frac{20x}{9}\right]=\frac{20}{9}$$

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