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Question Number 138643 by ArielVyny last updated on 15/Apr/21

Answered by mnjuly1970 last updated on 15/Apr/21

Commented by Dwaipayan Shikari last updated on 16/Apr/21

$$Greatsir!butinwrongplace$$

Answered by Dwaipayan Shikari last updated on 16/Apr/21

$$x-a=u$$$$K={\int }_{-\mathrm{\infty }}^{\mathrm{\infty }}\frac{sin\left(b(u+a)\right)}{u}du$$$$={\int }_{-\mathrm{\infty }}^{\mathrm{\infty }}\frac{sin\left(bu\right)cos\left(ab\right)+cos\left(bu\right)sin\left(ab\right)}{u}du$$$$=cos\left(ab\right){\int }_{-\mathrm{\infty }}^{\mathrm{\infty }}\frac{sin\left(bu\right)}{u}+0\left(oddfunction\right)$$$$=\pi cos\left(ab\right)$$

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