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Question Number 139445 by aliibrahim1 last updated on 27/Apr/21

Answered by mr W last updated on 27/Apr/21

$$u=xy$$$$\frac{du}{dx}=x\frac{dy}{dx}+y$$$$\frac{du}{dx}+3u^2=0$$$$-\frac{du}{u^2}=3dx$$$$\frac{1}{u}=3x+C$$$$\frac{1}{xy}=3x+C$$$$\frac{1}{2\times \frac{1}{2}}=3\times 2+C\Rightarrow C=-5$$$$\frac{1}{xy}=3x-5$$$$y=\frac{1}{x(3x-5)}$$$$y\left(1\right)=\frac{1}{1\times (3\times 1-5)}=-\frac{1}{2}$$

Commented by aliibrahim1 last updated on 27/Apr/21

$$thxbro$$

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