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Question Number 139619 by I want to learn more last updated on 29/Apr/21

Answered by mr W last updated on 30/Apr/21

P=pressure  V=volume of gas (air)  the larger the pressure, the smaller  the volume.  PV=constant

P=pressureV=volumeofgas(air)thelargerthepressure,thesmallerthevolume.PV=constant

Commented by mr W last updated on 30/Apr/21

Commented by mr W last updated on 30/Apr/21

say the cross−section of tube is A.  the volume of air in tube under   atmospheric pressure  is V_0 =40A, pressure is P_0 =77cm  the volume of air in tube in mercury  is V_1 =35A, pressure is P_1  with  P_1 =P_0 +(d−5)    P_0 V_0 =P_1 V_1   (P_1 /P_0 )=(V_0 /V_1 )=((40)/(35))  ((77+d−5)/(77))=((40)/(35))  d=5+(((40)/(35))−1)×77=16 cm  ⇒the tube is 16cm immersed.

saythecrosssectionoftubeisA.thevolumeofairintubeunderatmosphericpressureisV0=40A,pressureisP0=77cmthevolumeofairintubeinmercuryisV1=35A,pressureisP1withP1=P0+(d5)P0V0=P1V1P1P0=V0V1=403577+d577=4035d=5+(40351)×77=16cmthetubeis16cmimmersed.

Commented by I want to learn more last updated on 30/Apr/21

I really appreciate sir. Thanks for your time. God bless you.

Ireallyappreciatesir.Thanksforyourtime.Godblessyou.

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