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Question Number 14079 by Tinkutara last updated on 27/May/17

Commented by ajfour last updated on 27/May/17

$$tbresholdfrequency=$$$$(speedofe.m.wave)/\left(thresholdwavelength\right)$$$${\mathit{\nu }}_0=\frac{\mathit{c}}{{\mathit{\lambda }}_0}=\frac{\left(3\times {10}^{8}m/s\right)}{\left(6800\times {10}^{-10}m\right)}$$$$=\frac{300}{68}\times {10}^{14}Hz$$$$=\frac{75}{17}\times {10}^{14}Hz\approx 4.41\times {10}^{14}Hz.$$

Commented by Tinkutara last updated on 27/May/17

$$\mathrm{Thanks}.$$

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