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Question Number 144168 by bekzodjumayev last updated on 22/Jun/21

Answered by Olaf_Thorendsen last updated on 22/Jun/21

$$\mathrm{F}\left(x\right)=\int \frac{dx}{\arccos x}$$$$\mathrm{Let}x=\cos \theta$$$$\mathrm{F}\left(x\right)=-\int \frac{\sin \theta }{\theta }d\theta =-\mathrm{Si}\left(\theta \right)+\mathrm{C}$$$$\mathrm{F}\left(x\right)=-\mathrm{Si}\left(\arccos x\right)+\mathrm{C}$$

Commented by bekzodjumayev last updated on 22/Jun/21

$$Thankyou$$

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