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Question Number 145423 by olalekan2 last updated on 04/Jul/21

Answered by Olaf_Thorendsen last updated on 04/Jul/21

lim_(x→0)  (((√(1+x))+(1+x)^7 −2)/x)  = lim_(x→0)  ((1+(1/2)x+1+7x−2)/x)  = lim_(x→0)  (((1/2)x+7x)/x)  = ((15)/2)

limx01+x+(1+x)72x=limx01+12x+1+7x2x=limx012x+7xx=152

Answered by puissant last updated on 04/Jul/21

lim_(x→0)  (((1/(2(√(1+x))))+7(x+1)^6 )/1) = (1/2)+7=((15)/2)

limx0121+x+7(x+1)61=12+7=152

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