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Question Number 146017 by Khalmohmmad last updated on 10/Jul/21
Answered by Olaf_Thorendsen last updated on 10/Jul/21
F(x)+F(y)=F(x)F(y)(1)x=y⇒2F(x)=F2(x)⇔F(x)(F(x)−2)=0∀x,F(x)=0or2:impossiblebecauseF(12)=32⇒incompatibleconditions!WeveriflythatifF(12)=32:(1)F(12)+F(12)(=3)≠F(12)F(12)(=94)
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