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Question Number 148033 by iloveisrael last updated on 25/Jul/21

Commented by iloveisrael last updated on 25/Jul/21

((2^(2020) +1)/(2^(2018) +1)) + ((3^(2020) +1)/(3^(2018) +1)) +((4^(2020) +1)/(4^(2018) +1)) +((5^(2020) +1)/(5^(2018) +1)) +((6^(2020) +1)/(6^(2018) +1))=?

22020+122018+1+32020+132018+1+42020+142018+1+52020+152018+1+62020+162018+1=?

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