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Question Number 148113 by mathdanisur last updated on 25/Jul/21

Answered by liberty last updated on 25/Jul/21

$$Hatchedarea=\frac{1}{2}{\left(8\right)}^2\left(\frac{1}{2}\sqrt{3}\right)-\frac{1}{2}\pi {\left(4\right)}^2$$$$=16\sqrt{3}-8\pi$$

Commented by mathdanisur last updated on 25/Jul/21

$$ThanksSer,conyoupleasewrite$$$$alongerversion$$

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