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Question Number 148754 by mathdanisur last updated on 30/Jul/21

Commented by liberty last updated on 31/Jul/21

ans: 850

ans:850

Answered by liberty last updated on 31/Jul/21

 ((sin^6  36°)/(cos^6  36°)) + ((sin^6  72°)/(cos^6  72°)) =  (((1/2^6 )(2cos 72°sin 36°)^6 +(1/2^6 )(2sin 72°cos 36°)^2 )/((1/2^6 )(2cos 72°cos 36°)^6 ))  =(((sin 108°−sin 36°)^6 +(sin 108°+sin 36°)^6 )/((sin 18°(1−2sin 18°))^6 ))  =((cos^6  18°(1−2sin 18°)^6 +cos^6  18°(1+2sin 18°)^6 )/(sin^6  18°(1−2sin 18°)^6 ))  you can finish it

sin636°cos636°+sin672°cos672°=126(2cos72°sin36°)6+126(2sin72°cos36°)2126(2cos72°cos36°)6=(sin108°sin36°)6+(sin108°+sin36°)6(sin18°(12sin18°))6=cos618°(12sin18°)6+cos618°(1+2sin18°)6sin618°(12sin18°)6youcanfinishit

Commented by liberty last updated on 31/Jul/21

cos 18°=((√(2(√5)+10))/4)  sin 18°=(((√5)−1)/4)

cos18°=25+104sin18°=514

Commented by mathdanisur last updated on 31/Jul/21

Thank you Ser

ThankyouSer

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