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Question Number 148783 by 0731619 last updated on 31/Jul/21
Commented by hknkrc46 last updated on 31/Jul/21
(1)limh→0f(x+h)−f(x)h=limh→0−cos(x+h)+cosxh=limh→0cosx−cosx⋅cosh+sinx⋅sinhh=limh→0cosx(1−cosh)h+limh→0sinx⋅sinhh=cosx⋅limh→01−coshh+sinx⋅limh→0sinhh=cosx⋅0+sinx⋅1=sinx★d(−cosx)dx=sinx⇔∫sinxdx=−cosx+c
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