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Question Number 149510 by Tawa11 last updated on 05/Aug/21

Commented by Ar Brandon last updated on 06/Aug/21

$$36-4\times \frac{9}{2}={18\mathrm{cm}}^3$$

Commented by Tawa11 last updated on 06/Aug/21

$${\mathrm{cm}}^2?$$$$\mathrm{And}\mathrm{sir},\mathrm{how}\mathrm{did}\mathrm{you}\mathrm{get}4\times 5$$

Commented by Ar Brandon last updated on 06/Aug/21

$$\mathrm{Just}\mathrm{some}\mathrm{guess}\mathrm{work},\mathrm{hahaha}!$$$$\mathrm{Maybe}\mathrm{Mr}\mathrm{W}\mathrm{has}\mathrm{a}\mathrm{better}\mathrm{method}.$$

Commented by Tawa11 last updated on 06/Aug/21

$$\mathrm{Hahahaha}...\mathrm{Thanks}\mathrm{sir}.\mathrm{I}\mathrm{appreciate}.$$

Commented by MJS_new last updated on 06/Aug/21

$$\mathrm{counting}\mathrm{the}\mathrm{white}\mathrm{areas}$$$$\left(1\right)\mathrm{left}\mathrm{upper}\mathrm{corner}2\times 2=4$$$$\left(2\right)\mathrm{middle}\mathrm{square}+\mathrm{right}\mathrm{lower}\mathrm{corner}2\times 2=4$$$$\left(3\right)\mathrm{the}\mathrm{symmetric}\mathrm{small}‘‘{\mathrm{triangles}}^{″}$$$$2\times (2\times 2-2^2\pi /4)=8-2\pi$$$$\left(4\right)\mathrm{the}\mathrm{symmetric}\mathrm{big}‘‘{\mathrm{triangles}}^{″}$$$$2\times (4\times 4-4^2\pi /4)=32-8\pi$$$$\mathrm{sum}\mathrm{of}\mathrm{these}=48-10\pi =\mathrm{white}\mathrm{area}$$$$36-(48-10\pi )=10\pi -12=\mathrm{blue}\mathrm{area}$$

Commented by Tawa11 last updated on 06/Aug/21

$$\mathrm{Thanks}\mathrm{sir}.\mathrm{God}\mathrm{bless}\mathrm{you}.$$

Commented by Tawa11 last updated on 07/Aug/21

$$\mathrm{Sir}\mathrm{Mjs}\mathrm{and}\mathrm{ajfour}.\mathrm{Thanks},\mathrm{I}\mathrm{understand}\mathrm{your}\mathrm{solutions}\mathrm{very}\mathrm{well}\mathrm{now}.$$$$\mathrm{God}\mathrm{bless}\mathrm{you}.$$

Answered by ajfour last updated on 06/Aug/21

$$B=\frac{\pi }{2}{\left(4cm\right)}^2-2\{4{cm}^2-\frac{\pi }{4}{\left(2cm\right)}^2\}$$$$-4{cm}^2$$$$=(10\pi -12){cm}^2$$

Commented by Tawa11 last updated on 06/Aug/21

$$\mathrm{Thanks}\mathrm{sir}.\mathrm{God}\mathrm{bless}\mathrm{you}.$$

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