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Question Number 149720 by cherokeesay last updated on 06/Aug/21

Answered by mr W last updated on 06/Aug/21

(R−1)^2 +(R−2)^2 =R^2 R^2 −6R+5=0 (R−5)(R−1)=0 ⇒R=5, 1 (rejected) area of semicircle=((πR^2 )/2)=((25π)/2)

(R−1)2+(R−2)2=R2R2−6R+5=0(R−5)(R−1)=0⇒R=5,1(rejected)areaofsemicircle=πR22=25π2

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