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Question Number 150150 by Tawa11 last updated on 09/Aug/21

Commented by MJS_new last updated on 10/Aug/21

6×6−[4quarter circles r=2]−[3circles r=1]= =36−7π

6×6−[4quartercirclesr=2]−[3circlesr=1]==36−7π

Commented by Tawa11 last updated on 09/Aug/21

I got 14 ????

Igot14????

Commented by Tawa11 last updated on 10/Aug/21

Thank you sir. God bless you. Thanks for clarification.

Thankyousir.Godblessyou.Thanksforclarification.

Commented by Tawa11 last updated on 10/Aug/21

Thanks sir . I follow the same thing you did for me in Q149510

Thankssir.IfollowthesamethingyoudidformeinQ149510

Answered by maged last updated on 10/Aug/21

Blue Area=2(2×4−π)+(4×4−π×2^2 )+(2×2−π) Blue Area=(16−2π)+(16−4π)+(4−π) Blue Area=16+16+4−2π−4π−π Blue Area=36−7π Blue Area=36−7×((22)/7)=36−22 Blue Area=14 cm^2

BlueArea=2(2×4−π)+(4×4−π×22)+(2×2−π)BlueArea=(16−2π)+(16−4π)+(4−π)BlueArea=16+16+4−2π−4π−πBlueArea=36−7πBlueArea=36−7×227=36−22BlueArea=14cm2

Commented by Tawa11 last updated on 10/Aug/21

Thanks sir. God bless you.

Thankssir.Godblessyou.

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