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Question Number 150801 by puissant last updated on 15/Aug/21

Commented by puissant last updated on 15/Aug/21

$$findtan\theta please..$$

Commented by mr W last updated on 15/Aug/21

$$\theta isundeterminedwithgiven$$$$condition!$$

Commented by puissant last updated on 15/Aug/21

$$2DE=3EC$$

Commented by mr W last updated on 15/Aug/21

$$\theta ={\tan }^{-1}\frac{3}{5}+{\tan }^{-1}\frac{2}{5}$$$$\tan \theta =\frac{\frac{3}{5}+\frac{2}{5}}{1-\frac{3}{5}\times \frac{2}{5}}=\frac{25}{19}$$

Commented by puissant last updated on 15/Aug/21

$$nicesir..thankyou..$$

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